how to solve an exponential equation with one unknown in matlab

1 vue (au cours des 30 derniers jours)
Alice Faisal
Alice Faisal le 19 Juil 2018
I have an equation that need to be solved for rs, and I could'nt get the answer in matlab I have values for the other parameters and I need to get rs. But when computing it on MATLAB I dont get a correct answer This is the equation
exp((-pi*ra)/rs)+exp((-pi*rb)/rs)=1
ra=90.82*10^6 rb=90.23*10^6 so only rs in unknown

Réponse acceptée

Abraham Boayue
Abraham Boayue le 20 Juil 2018
Try the following code which uses Newton's method to find the root of the f(x) = 0.
close all;
clc;
N = 50;
ra = 90.82e6;
rb = 90.23e6;
a = pi*ra;
b = pi*rb;
tol = 1e-10;
x0 = 0;
x = x0;
xn = x;
for k = 1:N
f = exp(-a*x) + exp(-b*x)-1;
fd = -(a*exp(-a*x) + b*exp(-b*x));
x = x-f/fd;
err = abs(x-xn);
xn = x ;
if err<tol
break;
end
end
rs = 1/xn;
disp(rs)

Plus de réponses (1)

madhan ravi
madhan ravi le 20 Juil 2018
Modifié(e) : madhan ravi le 20 Juil 2018
%Try this:
syms rs
ra=90.82*10.^6
rb=90.23*10.^6
rs=vpasolve(exp((-pi.*ra)./rs)+exp((-pi.*rb)./rs)-1,rs)

Catégories

En savoir plus sur Numerical Integration and Differential Equations dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by