Effacer les filtres
Effacer les filtres

What does this error mean?

3 vues (au cours des 30 derniers jours)
Evan Mossel
Evan Mossel le 23 Juil 2018
Modifié(e) : Evan Mossel le 26 Juil 2018
I keep getting the error: Subscript indices must either be real positive integers or logicals.
days=10;
dy=-1;
hPlot1 = plot(dy,alt);
while dy<=days
%--calculate & display current time (UTC)
yr=2018;
mnth=1;
dy=dy+1;
hr=0;
min=0;
sc=0;
d=datetime(yr,mnth,dy,hr,min,sc);
%d=datetime('now');
%--covert and display current time in julian days
JD_TT=juliandate(d);
%--convert julian days to moon position
CooType='q2000';
[X,Y,Z]=moonpos(JD_TT,CooType);
%plot3(X,Y,Z);
%--convert to LLA coordinates, in degrees
alt=sqrt(X.^2+Y.^2+Z.^2);
xdata = get(hPlot1,'XData');
ydata = get(hPlot1,'YData');
set(hPlot1,'XData',[xdata dy],'YData',[ydata alt]);
end
altmax=max(ydata);
xmax=find(alt==altmax);
altmin=min(ydata);
xmin=find(alt==altmin);
  15 commentaires
Walter Roberson
Walter Roberson le 24 Juil 2018
Your xdata and ydata is going to include that initial nan value.
At the end of your loop, your xdata and ydata are not going to include the last dy and alt, because you change hPolt1's XData and YData after you assign to the temporary variable xdata and ydata.
Evan Mossel
Evan Mossel le 26 Juil 2018
Modifié(e) : Evan Mossel le 26 Juil 2018
I changed the xdata/ydata to Xdata/Ydata but this did not resolve the issue.
Update: I misunderstood. This fixed the issue

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Réponses (1)

Krithika A
Krithika A le 24 Juil 2018
You use min in your code. min is already a matlab function
  5 commentaires
Krithika A
Krithika A le 24 Juil 2018
Not specifically for min/max. Min/max can handle non-integers. It would be another function.
Evan Mossel
Evan Mossel le 24 Juil 2018
I believe it is the 'find' function. I will try to work it out.

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