Effacer les filtres
Effacer les filtres

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here I am trying to get the random matrix with the elements only 1 and 0 where none of columns and rows can be 0 only and also the number of 0s and 1s should be in a percentage of 30% and 70%.

2 vues (au cours des 30 derniers jours)
gkboy
gkboy le 7 Août 2018
Clôturé : MATLAB Answer Bot le 20 Août 2021
I am trying to get the random matrix with the elements only 1 and 0 where none of columns and rows can be 0s only or 1s only, and also the number of 0s and 1s should be in a percentage of 30% and 70%. They have to use probability
Requirements
  1. Random Matrix
  2. elements only 1s and 0s
  3. percentage of 0s: 1s is 3:7
  4. None of the columns and rows can be with only 0 and only 1. have to have mix
  2 commentaires
Walter Roberson
Walter Roberson le 8 Août 2018
When you say that you need to use probability, then do you mean that the fraction should be defined as exactly 30/100, that instead each entry should have a 0.3 probability of being 0?
"None of the columns and rows can be with only 0 and only 1. have to have mix"
That is impossible to achieve if there is only one row or only one column.
Any time you enforce that any one row or column cannot be all the same, you force yourself away from strict uniform distribution.

Réponses (2)

Thorsten
Thorsten le 8 Août 2018
Modifié(e) : Thorsten le 8 Août 2018
N=5; % size
ok = false;
maxiter = 1000;
i = 1;
while ~ok & i < maxiter
z=zeros(N); % start w/ none
o=randperm(numel(z),round(0.7*numel(z))); % 70% are 1's
z(o)=1;
ok = ~any(all(z) | all(z, 2)' | all(~z) | all(~z, 2)');
i = i + 1;
end

dpb
dpb le 8 Août 2018
N=5; % size
z=zeros(N); % start w/ none
o=randperm(numel(z),fix(numel(z)/2)); % 30% < ~50% < 70%
z(o)=1; % set the ones
>> ok=~(any(all(z) & all(z,2).')) % did we meet criteria?
ok =
logical
1
>>
Ayup...
  2 commentaires
Thorsten
Thorsten le 8 Août 2018
Modifié(e) : Thorsten le 8 Août 2018
ok is true if there are only 1's in row A but not only ones in the corresponding column A. But this is not ok. Also the OP asks for no columns/rows with all zeros.
dpb
dpb le 8 Août 2018
Yeah, the logic for the ok test isn't complete; the particular case was ok by inspection; it likely isn't a realistic ploy for practice; just a throwaway and probably shouldn't'a bothered...

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