how to build an if statement beyond the conditions

Hello Guys,

best wishes to all of us. I beg for help in solving this case. the case is in the form of conditioning logic.

I have to build a program line which is described in the conditions below:

suppose I have an input value in the form of a matrix Q = [0.2; 0.8; 1.4; 1.1; 2; 3; 3.9; 4.2; 5.5; 5; 4.7; 4; 3.5; 3.8; 3.1; 2.5; 1.9; 1.3; 0.7; 0], from the value of this input included in some of the conditions provided below

for input matrix Q uses looping

for example, the first loop, Q = 0.2

CONDITION A * if the value of Q <= 2 then the value of Z = 1200 * if the value of 2 <= Q <= 4 then the value of Z = 2000 * if the value of 4 <= Q <= 6 then the value of Z = 3500

so the value of Z for Q = 0.2 is Z = 1200

and from these conditions, must also meet the following conditions

CONDITION B * if the current Q value is Q value [example in row 4 matrix] then Z value = previous Z value * if the current Q value = from the previous Q value then the Z value is used by the current Z value

and then the program must also meet the following conditions:

CONDITION C * if the Z value in the loop has used the last condition Z (Z = 3500) then the Z value used for looping after that is Z = 3500 [CONDITION A, B, C NOT IN THE PROCESS]

For example in the loop line Q matrix 11 (ie for Q = 3.5) so Z used Z = 3500, not 2000

Please help me

Thanks

[madhan ravi]

Could you upload your code?

[Stephen23]

@Muhammad Dzul Akbar: what have you tried so far?

[Muhammad Dzul Akbar]

I have tried learning from books and videos from YouTube, but for CONDITION C which is an obstacle for me.

can you give me a clue?

[Muhammad Dzul Akbar]

@madhan ravi

for i = 1:size(Q,1); x = Q(i,1); y = Q(i-1,1);

       K= zeros(20,1);

       if x <= 2
           K(i,1) = 1200
        elseif x > 2 & x <= 4
           K(i,1) = 2000          
        else x > 4 & x <= 6
           K(i,1) = 3500   
       end

       if x < y 
          K(i,1) = K(i-1,1)
       elseif x > y
          K(i,1)= K(i,1) 
       End
End

for condition C, i can't

Answer 1

[madhan ravi]

    Q = [0.2; 0.8; 1.4; 1.1; 2; 3; 3.9; 4.2; 5.5; 5; 4.7; 4; 3.5; 3.8; 3.1; 2.5; 1.9; 1.3; 0.7; 0]

    K= zeros(20,1);

    for i = 2:size(Q);
        x(i) = Q(i);
        y(i) = Q(i-1);

           if x(i) <= 2
               K(i) = 1200;
            elseif x(i) > 2 & x(i) <= 4
               K(i) = 2000;          
           elseif x(i) > 4 & x(i) <= 6
               K(i) = 3500;

           elseif x(i) < y(i) 
              K(i) = K(i-1);
           elseif x(i)> y(i)
              K(i)= K(i);
           end
    end

    K_before = K

    for i = 1:length(K)

        if K(i)==3500

            K(i+1)=K(i);
        else
            continue
        end
    end

K_after = K

[madhan ravi]

After running the code , tell the additional requirements you need.

[Muhammad Dzul Akbar]

tell ? can you give me an example ?

[madhan ravi]

Is the code working?Is this the result you need?

[Muhammad Dzul Akbar]

yes, its work, but only for Condition A and B, not for condition C.

[Muhammad Dzul Akbar]

the results are in accordance with what I wrote in the first question

[madhan ravi]

So right now if the K’th element is 3500 the next event should be 3500. Am I right?

[Muhammad Dzul Akbar]

yes, right

[madhan ravi]

Check the code now , I edited it.

[madhan ravi]

@Muhammed does it work for your requirements now?

[madhan ravi]

If it does then accept the answer if not tell what should be done.

[Muhammad Dzul Akbar]

Ok thanks @madhan ravi, it works correctly

[madhan ravi]

Your welcome.

Answer 2

[Pierre845]

Not sure why you cannot find a solution, it's fairly basic use of a loop.

Do first a if .. then .. end using the matrix Q

Then either a for or while loop using the Z from previous step.

[Muhammad Dzul Akbar]

I have tried to compile the code, but not in accordance with the conditions needed.

could you help me?