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Effacer les filtres

interpolate 3 dimensional arrays (in time and space)

4 vues (au cours des 30 derniers jours)
wave_buoys
wave_buoys le 28 Août 2018
Commenté : wave_buoys le 29 Août 2018
Hi all,
I have 3D matrix 180x90x120 which is equal to lonxlatxtime. In space, the data has 1 degree resolution (e.g. longitude ranges from 1 to 180), while the time interval is 3 hours (e.g. 3h, 6h, 9h.....).
Now I want to interpolate data to get a finer resolution of 0.5 degree and with 1-hour interval, so the new matrix would be 360x180x360.
Could you please help?
Thanks
  4 commentaires
Matt J
Matt J le 28 Août 2018
Modifié(e) : Matt J le 28 Août 2018
No, do not use griddata for this. KL's suggestion of griddedInterpolant was appropriate. See also my second answer.
Matt J
Matt J le 28 Août 2018
Modifié(e) : Matt J le 28 Août 2018
Now I want to interpolate data to get a finer resolution of 0.5 degree and with 1-hour interval, so the new matrix would be 360x180x360.
Those will not be the new dimensions. If you sample from 1 to 180 at intervals of 0.5, you will obtain 359 points, not 360. Similarly for the other dimensions.

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Réponse acceptée

Matt J
Matt J le 28 Août 2018
Modifié(e) : Matt J le 28 Août 2018
F=griddedInterpolant(yourData);
qlon=(1:.5:180);
qlat=(1:.5:90);
qtime=(1:1/3:120);
newData=F({qlon,qlat,qtime});
  2 commentaires
wave_buoys
wave_buoys le 29 Août 2018
THIS WORKS FOR ME!!!!!!!! THANKS MATT
wave_buoys
wave_buoys le 29 Août 2018
Dear Matt J,
Sorry. It works but the outcomes are not as I expected. Particularly the new results look weird. Perhaps I also misunderstood about the input matrix format. To be corrected, the 3D matrices I mentioned, for instance, 180x90x120 contains 120 2D arrays size (180x90) for monthly wind speeds in Longitude and Latitude direction. These 120 matrices correspond to a 1D time matrix (which is separated): 0h 6h 12h 18h.....720h..
So when I use:
v = winddata % (size: 180x90x120)
F= griddedInterpolant(v)
qlon=(1:.5:180)
qlat=(1:.5:90);
qtime=(1:1/3:120);
newwinddata=F({qlon,qlat,qtime});
it does not work properly because time does not present in griddedInterpolant(v).
May you help more? Thanks

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Plus de réponses (1)

Matt J
Matt J le 28 Août 2018
Modifié(e) : Matt J le 28 Août 2018
You could download IMRESIZEN, and then do things like,
>> A=rand(180,90,120); B=imresizen(A,[2,2,3]); whos B
Name Size Kilobytes Class Attributes
B 360x180x360 182250 double
  2 commentaires
wave_buoys
wave_buoys le 28 Août 2018
Modifié(e) : Matt J le 28 Août 2018
Thanks Matt, but it does not for my situation because Imresizen just scales up the data.
Has anyone done something similar to this? May you help?
Thanks
Matt J
Matt J le 28 Août 2018
How is that different from what you are trying to do?

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