Creating adjacency from the matrix containing not sequence number
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Vishnu Kant
le 29 Août 2018
Réponse apportée : Bruno Luong
le 4 Sep 2018
I have a 4x6 matrix (directed network) similar to the following example:So first column represent individuals and each rows represent individual friendship with other individuals so first row represent individual 1 friendship with 2 and 5 and similarly row 3 represent individual 5 friendship with individuals 2 and 6. Zeros have no meaning.
[ 1 2 0 5 0 0;
2 1 0 0 5 6;
5 2 6 0 0 0;
6 1 2 0 0 5; ]
So now since there are four individuals I want *4x4 adjacency matrix representing friendship meaning 0 indicating no friendship and 1 indicating friendship*. So first row in the following represent individual 1 friendship with 2,5 as 1 meaning they are friend and 0 for 6 they are not friend. Similarly row two represent friendship individual 2 with 1,5 and 6 as 1 meaning he/she is friend with all the individuals.
[ 0 1 1 0;
1 0 1 1;
0 1 0 1;
1 1 1 0; ]
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Réponse acceptée
Sachin Meena
le 4 Sep 2018
You can use the function containers.Map to map individuals to indices (in this case, 1 maps to 1, 2 to 2, 5 to 3, and 6 to 4), and then traverse your relationship matrix and assign values to adjacency matrix accordingly. Use the map to convert related person to index in adjacency matrix.
c=containers.Map;
c('2')=2;
>> c('2')
ans =
2
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Bruno Luong
le 4 Sep 2018
A=[ 1 2 0 5 0 0;
2 1 0 0 5 6;
5 2 6 0 0 0;
6 1 2 0 0 5; ]
u=unique(A(:,1));
[~,J]=ismember(A(:,2:end),u);
[i,~]=find(J);
j=J(J>0);
accumarray([i,j],1)
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