Matlab problem. Command find

Hey. I have a problem. I have an array with dimensions A = 1 x 10 and an array B = 12015x10. My question is: how to find the values of the B array, which are smaller than the value of the array A. I tried to do it with the find command:

c = find(A<B)

but the following message is displayed: "Matrix dimensions must agree".

PS. Sorry for my language but still learning.

[Anusha Sridharan]

[Answers Dev] Restored edits

Hey. I have a problem. I have an array with dimensions A = 1 x 10 and an array B = 12015x10. My question is: how to find the values of the B array, which are smaller than the value of the array A. I tried to do it with the find command:

c = find(A<B)

but the following message is displayed: "Matrix dimensions must agree".

PS. Sorry for my language but still learning.

Answer 1

[Stephen23]

You probably need to use bsxfun:

bsxfun(@lt,B,A)

[Przemek Tomaszewski]

Thank you for your help. Only values are shown in the form 0 and 1. And how to make these values displayed in the form of valid values.

[Stephen23]

"Only values are shown in the form 0 and 1. And how to make these values displayed in the form of valid values."

What are "valid values"?

Going back to your original question: "how to find the values of the B array, which are smaller than the value of the array A", you just need to do this:

idx = bsxfun(@lt,B,A);
B(idx)

that will give you all values that are less than some values of A. But I suspect that is not what you really want: you need to be more precise in your specification: what does "...smaller than the value of the array A" really mean? Smaller than all values of A? Smaller than the values of A in the same column? Is it acceptable if there are different numbers of values returned for each column?

[Przemek Tomaszewski]

If I have an array 2x2 A = [2 3; 4 5]. This, if I would look for values greater than 3, would display such a table [0 0 1 1]. And what I mean is that the values are displayed to me [4 5].

[Przemek Tomaszewski]

I wrote this badly. Now I would like to have an array of C, I would like to find values that will compensate for this "1".

idx=bsxfun(@gt, B, A);
d=c(idx);

Only the values from column 1 are displayed. How to make it display from all columns (10)?

[Stephen23]

"If I have an array 2x2 A = [2 3; 4 5]. This, if I would look for values greater than 3, would display such a table [0 0 1 1]. And what I mean is that the values are displayed to me [4 5]."

Your example (with a scalar B) is easy to achieve:

>> A = [2,3;4,5];
>> B = 3;
>> C = A(A>B)
C =
   4
   5

However this only works as long as B is a scalar, whereas in your original question you state that "B = 12015x10". and "A = 1x10". To deal with those non-scalar arrays you would need to answer the questions I asked you in my previous comment.

Consider these arrays:

>> A = [1,3,5]
A =
   1   3   5
>> B = [0,2,4;9,7,5;6,6,6;3,2,1]
B =
   0   2   4
   9   7   5
   6   6   6
   3   2   1

Please show the expected output.