Problem plotting with 4 columns

6 vues (au cours des 30 derniers jours)
D.J
D.J le 1 Sep 2018
Commenté : jonas le 1 Sep 2018
Hi all, I am trying to plot this function, but getting so many errors. I first got this error: "A numeric or double convertible argument is expected" So I converted the table to array, then I got this error: "Size mismatch in Param Cell / Value Cell pair" I ran out of ideas ! Basically, I need x to be the dates (using standard formats, all days showing) y to show 3 columns: min, max and difference between them Here is my code, I have also attached the data file. Any help would be highly appreciated ! Thanks a lot!
clear
clc
Table_Q7=readtable('Test_data7.csv');
x_tbl=Table_Q7(6:end,2);
%tbl 2 array
x=table2array(x_tbl);
%ymin tbl2array
y_min_tbl=Table_Q7(6:end,3);
y_min=table2array(y_min_tbl);
%ymax tbl2array
y_max_tbl=Table_Q7(6:end,4);
y_max=table2array(y_max_tbl);
%y difference between max and min
y_diff_tbl=Table_Q7(6:end,5);
y_diff=table2array(y_diff_tbl);
%y=table2array(y_tbl)
plot(x,[y_max,y_min,y_diff])

Réponse acceptée

jonas
jonas le 1 Sep 2018
Modifié(e) : jonas le 1 Sep 2018
Here's a solution using textscan instead of readtable
fid=fopen('Test_data7.csv')
formatSpec='%s%d%d%d';
out=textscan(fid,formatSpec,...
'delimiter',',',...
'MultipleDelimsAsOne',true,...
'collectoutput',true,...
'HeaderLines',6)
fclose(fid);
t=datetime(out{1});
data=out{2};
plot(t,data)
  2 commentaires
D.J
D.J le 1 Sep 2018
Perfect ! Thanks a million ...Much appreciated !!
jonas
jonas le 1 Sep 2018
No problem, happy to help!

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Plus de réponses (2)

jonas
jonas le 1 Sep 2018
Modifié(e) : jonas le 1 Sep 2018
The problem is with your data import, as the csv is a bit messy. This is the cleanest import out of many attempts. Results attached.
opts=detectImportOptions('Test_data7.csv','Delimiter',',','NumHeaderLines',5)
opts.ExtraColumnsRule='ignore'
opts.SelectedVariableNames={'Date','MinTemp','MaxTemp','DiffTemp'}
T=readtable('Test_data7.csv',opts);
TT=table2timetable(T);
plot(TT.Date,TT.Variables)
  12 commentaires
jonas
jonas le 1 Sep 2018
Thanks. That output is not very useful. I'll come back with another solution shortly.
jonas
jonas le 1 Sep 2018
Posted a separate answer using textscan. I understand your concern. I used release 2013a for 3-4 years until I was finally forced to update as I needed to use the latest image processing functions. I saved the old release just-in-case, but I have never had to use it :)

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D.J
D.J le 1 Sep 2018
Thanks a lot Jonas. I really appreciate your help !
  1 commentaire
jonas
jonas le 1 Sep 2018
If any one of the answers solved your problem please accept it ;)

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