index exceeds array bound meaning?
97 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Chaitanya Lakeshri
le 2 Sep 2018
Commenté : Walter Roberson
le 28 Nov 2022
what is the meaning of index exceeds array bound
3 commentaires
Walter Roberson
le 29 Mar 2022
You have
x =optimvar('x',2,'LowerBound',[0 0],'UpperBound',[5 5]);
so you say that x is a vector of 2 optimization variables. Your upper bound and lower bound are both vectors of length 2, which is consistent. x is not ambiguous: it really is length 2.
obj = x(1)^2 + x(2)^2 + x(3)^2;
but there you try to use x(3)^2 which would require that x be of length 3 or more.
Your constaints A, B, C all require that x has at least 3 elements.
x0.x = [0 0];
but that says that the initial value is a vector of length 2.
You need to decide whether your function involves 2 variables or 3 variables.
Réponse acceptée
madhan ravi
le 2 Sep 2018
Modifié(e) : madhan ravi
le 2 Sep 2018
It means that the index number is more than the array elements.
An example:
x=[1:10]
x(11)
Your array has 10 elements but you try accessing the 11th element.
9 commentaires
Umar Farooq
le 28 Nov 2022
Erro
Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in New_Arya_Paris (line 27)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
-------------------------------------------------------
Problm
w=[1.000 0.993 0.984 0.968 0.938 0.870 0.787 0.766 0.660 0.553 0.383 0.298 0.234 0.191 0.085]
d=[2.000 1.000 0.500 0.250 0.150 0.053 0.054 0.039 0.023 0.013 0.008 0.006 0.005 0.004 0.001]
di=d.*100
wi=(w.*1000)
ni=15
for j=1:1;
for i=1:(ni-1)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
end
end
Walter Roberson
le 28 Nov 2022
You create a row vector, 1 row multiple columns. but index it as multiple rows with one column.
Plus de réponses (1)
CECILIA ABASCAL FALAGAN
le 16 Août 2020
Good morning,
I would like to obtain the real time of my computer to later carry out operations and obtain the elapsed time. I have used the "datetime" command but I can't separate the time from the date and use it for this purpose. Any suggestion? I would be very grateful
1 commentaire
Walter Roberson
le 16 Août 2020
Most of the time, you would use tic and toc to obtain elapsed time.
You can also use
tin = clock;
do your code
tout = clock;
how_long = etime(tout, tin) %seconds
You can also
tin = datetime();
do your code
tout = datetime();
how_long = seconds(tout - tin) %seconds
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!