reflection coeff. value

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Arvind Sharma
Arvind Sharma le 3 Sep 2018
Commenté : madhan ravi le 3 Sep 2018
how to solve this equation n=[1 2 3 4 5 6]; kz=2*pi*n(i) equation RTE=( Kz,i-kz,i+1)/(Kz,i+kz,i+1); how to solve RTE
  2 commentaires
Dimitris Kalogiros
Dimitris Kalogiros le 3 Sep 2018
I'm afraid that you have to rewrite your question with a more comprehensive way.
Arvind Sharma
Arvind Sharma le 3 Sep 2018
i am providing you doc file

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Réponse acceptée

madhan ravi
madhan ravi le 3 Sep 2018
Modifié(e) : madhan ravi le 3 Sep 2018
Maybe try the following:
n=[1 2 3 4 5 6];
ki=2.*pi.*n
k=1.2
kz=sqrt((ki.^2-k.^2))
for i= 1:length(kz)-1
RTE(i)=(kz(i)-kz(i+1))/(kz(i)+kz(i+1));
end
RTE
  2 commentaires
Arvind Sharma
Arvind Sharma le 3 Sep 2018
i have attached new file to make easier for you
madhan ravi
madhan ravi le 3 Sep 2018
check now

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