Effacer les filtres
Effacer les filtres

I need to check cell value along each diagonal. then if condition which I have define is satisfying, cells which have NaN value should replace by interpolation of cells beside NaN value cells.

1 vue (au cours des 30 derniers jours)
for q=1:nBinsY-2
if q==1
for p=3:nBinsX
s=p;
for i = 1:s-1
j = p;
if ~isnan(minz(i,j)) && isnan(minz(i+1,j-1))
for jj=2:p-1
if ~isnan(minz(i+jj,j-jj))
dz=minz(i,j)-minz(i+jj,j-jj);
dx=minx(i,j)-minx(i+jj,j-jj);
dy=miny(i,j)-miny(i+jj,j-jj);
ddi=sqrt(square(dx)+square(dy));
if abs(dz)<1 && abs(ddi)<5
sl=dz/ddi;
ddx=dx/(jj);
ddy=dy/(jj);
for r=1:jj-1
minz(i+r,j-r)=minz(i,j)+(sl*r);
minx(i+r,j-r)=minx(i,j)+(ddx*r);
miny(i+r,j-r)=miny(i,j)+(ddy*r);
end
else
continue
end
else
continue
end
i=i+jj;
j=j-jj;
end
else
continue
end
p=p-1;
end
end
else
p=nBinsX
for i = q:p+1
j=p;
if ~isnan(minz(i,j)) && isnan(minz(i+1,j-1))
for jj=2:p-1
if ~isnan(minz(i+jj,j-jj))
dz=minz(i,j)-minz(i+jj,j-jj);
dx=minx(i,j)-minx(i+jj,j-jj);
dy=miny(i,j)-miny(i+jj,j-jj);
ddi=sqrt(square(dx)+square(dy))
if abs(dz)<1 && abs(ddi)<5
sl=dz/ddi;
ddx=dx/(jj);
ddy=dy/(jj);
for r=1:jj-1
minz(i+p,j-p)=minz(i,j)+(sl*r);
minx(i+p,j-p)=minx(i,j)+(ddx*r);
miny(i+p,j-p)=miny(i,j)+(ddy*r);
end
else
continue
end
else
continue
end
i=i+jj;
j=j-jj;
end
else
continue
end
p = p-1;
end
end
end

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