Hello. I'm trying to swap the first two numbers of the first and second rows of this test matrix with the last two numbers of the second and third rows. Is there any way to swap these numbers in a matrix that's not one row and/or not on the same row?
x = [1 2 3 4 5;
6 7 8 9 10;
11 12 13 14 15]
The result should be:
x = [9 10 3 4 5;
14 15 8 1 2;
11 12 13 6 7]

 Réponse acceptée

Stephen23
Stephen23 le 12 Sep 2018
Modifié(e) : Stephen23 le 12 Sep 2018

1 vote

>> x = [1,2,3,4,5;6,7,8,9,10;11,12,13,14,15]
x =
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
>> x([1,4,11,14]) = x([11,14,1,4])
x =
9 10 3 4 5
6 7 8 1 2
11 12 13 14 15
You can easily generate those linear indices with sub2ind.

1 commentaire

The code to do it was actually this:
x([1,2,4,5,11,12,14,15]) = x([11,12,14,15,1,2,4,5])
...but thanks! I got the gist of it!

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Plus de réponses (1)

Bruno Luong
Bruno Luong le 12 Sep 2018
Modifié(e) : Bruno Luong le 12 Sep 2018

1 vote

[x(1:2,1:2) x(2:3,4:5)] = deal(x(2:3,4:5),x(1:2,1:2))

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