How to extract complex cell data into a new variable?

4 vues (au cours des 30 derniers jours)
Austin Sowers
Austin Sowers le 17 Sep 2018
Commenté : Austin Sowers le 17 Sep 2018
I have a variable with 2000 columns. In each of the 2000 columns, there is a 1x13 cell. Within each 1x13 cell, there is a varying size double (Nx1), where N is any number. I would like to have the very 1st number within the (Nx1) double, in each of the 1x13 cells, for all 2000 columns. I would like this to result in a new cell variable with 13 columns of double 2000x1 data sets. i.e. (2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double, 2000x1 double,).
Because this is kind of confusing, I attached my code so you can open the variable yourself. To run it, it needs nodes.txt and pipes.txt. The variables name after you run the code, is "H"

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Rik
Rik le 17 Sep 2018
Using a double loop to accomplish this is still reasonably fast:
%generate a random H
s1=2000;s2=13;
H=cell(s1,1);
for n=1:s1
H{n}=cell(1,s2);
for m=1:s2
H{n}{m}=rand(randi(100),1);
end
end
clc
tic
output=zeros(size(H,1),size(H{1},2));
for n=1:size(output,1)
for m=1:size(output,2)
output(n,m)=H{n}{m}(1);
end
end
O=mat2cell(output,n,ones(m,1));
  3 commentaires
Austin Sowers
Austin Sowers le 17 Sep 2018
Yes. If you could please correct this, I would appreciate it very much!! I am a rookie matlab guy. It is a problem I have been working on for some time and will help me a lot. Thank you again.
Austin Sowers
Austin Sowers le 17 Sep 2018
Actually, I just transposed my "H" and it worked. Thank you so much!

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