taylor series method expansion
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I am using the following code for taylor series
function [T,Y] = taylor(f,a,b,ya,m)
h = (b - a)/m;
T = zeros(1,m+1);
Y = zeros(1,m+1);
T(1) = a;
Y(1) = ya;
for j=1:m
tj = T(j);
yj = Y(j);
D = feval('df',tj,yj);
Y(j+1) = yj + h*(D(1)+h*(D(2)/2+h*(D(3)/6+h*D(4)/24)));
T(j+1) = a + h*j;
end
At command prompt i am giving the values as follows and getting error
>> syms x y;
>> f=4*x^3+1
f =
4*x^3 + 1
>> taylor(f,0,1,1.5,4)
Error using sym/taylor (line 99)
The value of 'x' is invalid. It must satisfy the function: @(x)isvector(x)&&isAllVars(x).
9 commentaires
Walter Roberson
le 19 Sep 2018
Well you could if you had a variable name to take the derivative with respect to, and you had some reason for D(1) being different from D(2), D(3) etc.
Réponses (1)
Walter Roberson
le 18 Sep 2018
You are somehow invoking the symbolic toolbox taylor routine instead of your own. Make sure that you match file name with function name and that your path is correct to prioritize your own function.
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