The following works well:
A = [1 2 3 4 5];
A > 2
0 0 1 1 1
But, how can i mask A==1 and A ==3, so getting the following result (for example putting the values that are to be masked in a vector):
mask_array = [1 2];
A ~= mask_array
0 1 0 1 1

 Réponse acceptée

Image Analyst
Image Analyst le 23 Sep 2018
Modifié(e) : Image Analyst le 23 Sep 2018
Try this:
mask = (A == 1) | (A == 3) % 1 for either 1 or 3
Or maybe you mean
mask = (A == 1) | (A >= 3) % 1 for 1 or anything 3 or more.

1 commentaire

Rightia Rollmann
Rightia Rollmann le 24 Sep 2018
Modifié(e) : Rightia Rollmann le 24 Sep 2018
Thanks! I meant the first solution. Is there a more compact way to write this code? (There are a large number of values that should be masked and it would be more convenient to write something like below)
OR(A == 1,3,...)

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