Effacer les filtres
Effacer les filtres

how to calculate the convolution of two signal without using CONV() ?

171 vues (au cours des 30 derniers jours)
Hi everyone, i was wondering how to calculate the convolution of two sign without Conv();. I need to do that in order to show on a plot the process. i know that i must use a for loop and a sleep time, but i dont know what should be inside the loop, since function will come from a pop-up menu from two guides.(guide' code are just ready);
option = get(handles.popupmenu1,'value');
option2 = get(handles.popupmenu2,'value');
// something that switch the func.
conv(x,h);
//plot the conv.
  4 commentaires
Image Analyst
Image Analyst le 25 Sep 2018
Not sure what that means. Why do you need a delay? Do you want to show a set of boxes representing the kernel moving along over the top of another set of boxes representing the signal? Doing the convolution is one thing (a really easy thing), but providing the animation, if that is what is required will be a lot harder.
Synchro_mdn
Synchro_mdn le 25 Sep 2018
Lets leave out that part, I just really need to know how to set the for loop for two different signal.

Connectez-vous pour commenter.

Réponse acceptée

Dimitris Kalogiros
Dimitris Kalogiros le 25 Sep 2018
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
  3 commentaires
Allard Quek
Allard Quek le 12 Mar 2022
the first characters represent the colour and the second characters represent the shape:
'-b^': blue triangle
'-ro': red circle
'-ms': magenta square
maryam alyammahi
maryam alyammahi le 16 Fév 2023
How to make the graph starts from zero not one?

Connectez-vous pour commenter.

Plus de réponses (5)

Sk Group
Sk Group le 25 Oct 2021
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output

Manoj Manu
Manoj Manu le 16 Août 2021
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');

Kiran K V
Kiran K V le 28 Juin 2022

clear all;

clc;

x = input ('Enter the first signal/sequence ');

h = input('Enter the second signal/sequence ');

Find the length of the individual signals, and thus the output

[~,L]= size (x);

[~,M] = size (h);

len y = L + M - 1

y = zeros (1, len_y);

len = 1:1en_y;

for i = 0 / l * eny

for j = 0/1 * eny

if ((i-j+1)>0 && (i-j+1)<=M && (j+1)<=L) y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1);

end

end

end

disp (y)

stem (len, y)

  1 commentaire
Or Baron
Or Baron le 31 Juil 2022
what do you mean by y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1); ? what does ,^ mean?

Connectez-vous pour commenter.


Muhammad
Muhammad le 27 Août 2023
1 2 3
-1 2 3

Mehmet Eren Dikmen
Mehmet Eren Dikmen le 28 Mar 2024
Hi guys i need to find a matlab code which can take 2 inputs of 2 different signals and generates and y(t) signal. This y(t) signal must be a another signal. So I'm basicaly looking for a signal for output. This is soooo urgent

Produits


Version

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by