how to calculate the convolution of two signal without using CONV() ?
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Synchro_mdn
le 25 Sep 2018
Réponse apportée : Mehmet Eren Dikmen
le 28 Mar 2024
Hi everyone, i was wondering how to calculate the convolution of two sign without Conv();. I need to do that in order to show on a plot the process. i know that i must use a for loop and a sleep time, but i dont know what should be inside the loop, since function will come from a pop-up menu from two guides.(guide' code are just ready);
option = get(handles.popupmenu1,'value');
option2 = get(handles.popupmenu2,'value');
// something that switch the func.
conv(x,h);
//plot the conv.
4 commentaires
Image Analyst
le 25 Sep 2018
Not sure what that means. Why do you need a delay? Do you want to show a set of boxes representing the kernel moving along over the top of another set of boxes representing the signal? Doing the convolution is one thing (a really easy thing), but providing the animation, if that is what is required will be a lot harder.
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Dimitris Kalogiros
le 25 Sep 2018
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
3 commentaires
Allard Quek
le 12 Mar 2022
the first characters represent the colour and the second characters represent the shape:
'-b^': blue triangle
'-ro': red circle
'-ms': magenta square
Plus de réponses (5)
Manoj Manu
le 16 Août 2021
close all
clearvars
%x=input('Enter x: ')
x=sin(2*pi*0.1.*(1:1:11));
%h=input('Enter h: ')
h=[1 2 3 4 5 3 1 -1];
% convolution
m=length(x);
n=length(h);
X=[x,zeros(1,n)];
H=[h,zeros(1,m)];
for i=1:n+m-1
Y(i)=0;
for j=1:m
if(i-j+1>0)
Y(i)=Y(i)+X(j)*H(i-j+1);
else
end
end
end
% plot results
figure;
subplot(3,1,1); stem(x, '-b^'); xlabel('n');
ylabel('x[n]'); grid on;
subplot(3,1,2); stem(h, '-ms');
xlabel('n'); ylabel('h[n]'); grid on;
subplot(3,1,3); stem(Y, '-ro');
ylabel('Y[n]'); xlabel('----->n'); grid on;
title('Convolution of Two Signals without conv function');
1 commentaire
Sk Group
le 25 Oct 2021
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output
For complete detailed post visit: https://www.swebllc.com/convolution-without-function-in-matlab/
0 commentaires
Kiran K V
le 28 Juin 2022
clear all;
clc;
x = input ('Enter the first signal/sequence ');
h = input('Enter the second signal/sequence ');
Find the length of the individual signals, and thus the output
[~,L]= size (x);
[~,M] = size (h);
len y = L + M - 1
y = zeros (1, len_y);
len = 1:1en_y;
for i = 0 / l * eny
for j = 0/1 * eny
if ((i-j+1)>0 && (i-j+1)<=M && (j+1)<=L) y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1);
end
end
end
disp (y)
stem (len, y)
1 commentaire
Or Baron
le 31 Juil 2022
what do you mean by y(i+1)=y(i+1)+x(j+1),^ * h(i-j+1); ? what does ,^ mean?
Mehmet Eren Dikmen
le 28 Mar 2024
Hi guys i need to find a matlab code which can take 2 inputs of 2 different signals and generates and y(t) signal. This y(t) signal must be a another signal. So I'm basicaly looking for a signal for output. This is soooo urgent
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