Changing letters to other letters with regexprep

4 vues (au cours des 30 derniers jours)
Ryoma Kawakami
Ryoma Kawakami le 28 Sep 2018
Commenté : Walter Roberson le 28 Sep 2018
I'm trying to change letters in a string to different ones with one line of code. I simplified my code down to the following:
regexprep('ab',{'a','b'},{'b','c'});
Ideally, this would output 'bc'. Currently, regexprep runs through the string twice and ends up outputting 'cc'.
Is there any way to prevent this from happening? Is it possible with regexprep? Also, I would prefer to keep the letters as strings, as I'm planning on using the 'preservecase' condition.

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Stephen23
Stephen23 le 28 Sep 2018
Modifié(e) : Stephen23 le 28 Sep 2018
You don't need regexprep, using ismember and indexing is simpler:
>> str = 'a':'z'
str = abcdefghijklmnopqrstuvwxyz
>> old = 'bcd';
>> new = 'abc';
>> [X,Y] = ismember(str,old);
>> str(X) = new(Y(X))
str = aabcefghijklmnopqrstuvwxyz
Note that this works efficiently for any characters, not just a limited subset. In order to use regexprep you would probably need to use a dynamic replacement expression.
  1 commentaire
Walter Roberson
Walter Roberson le 28 Sep 2018
Well, any characters representable in the first 65536 code points ;-) If you have codepoints beyond that, such as Linear B or CJK Unified Ideograms like ? then you would need more work.

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Plus de réponses (2)

OCDER
OCDER le 28 Sep 2018
Note that regexprep will replace things Sequentially.
regexprep('ab',{'a','b'},{'b','c'});
ab -> bb -> cc
To fix, reverse order like this:
regexprep('ab',{'b', 'a'},{'c', 'b'});
ab -> ac -> bc
  2 commentaires
Ryoma Kawakami
Ryoma Kawakami le 28 Sep 2018
I apologize for not mentioning what I exactly planned to do after this.
I want regexprep (or something similar) to work for any shift in letters (such as 'bcd' to 'abc'), which means that reversing the order of evaluation wouldn't work.
OCDER
OCDER le 28 Sep 2018
replace('a b c', {'a', 'b', 'c'}, {'c', 'a', 'b'})

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Walter Roberson
Walter Roberson le 28 Sep 2018
old = 'bcd';
new = 'abc';
lookup = char(0:255);
lookup(old+1) = new;
str = 'a':'z'
str = lookup(str+1)
You do not need to add 1 if you are willing to omit the possibility of char(0) being in the string.
  2 commentaires
Stephen23
Stephen23 le 28 Sep 2018
Modifié(e) : Stephen23 le 28 Sep 2018
Interesting. This will not work for characters >255 (or whatever limit you pick).
Walter Roberson
Walter Roberson le 28 Sep 2018
Correct. You can extend it to max(str) easily, though.

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