Cumulative sum with conditions
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I am counting a number of 1's in an array.
But I want to count the cumulative sums only when the number of 1's are followed by a sequence of zeros.
% For instance,
h1=[1 0 0]
h2=[1 1 0]
h3=[1 1 1]
h4=[0 0 1]
h5=[0 1 0].
I want to count the cumulative sums (S) of those arrays as follows.
% The ideal outputs are:
S1= 1
S2= 2
S3= 0
S4= 0
S5= 0
since h2: h4 do not meet the condition of 1's followed by 0's.
I would truly appreciate if any one could advise me an effective way of programming the conditional sums.
1 commentaire
Rik
le 3 Oct 2018
So you have these as numbered variables? Then you should really have them in a single array. Also, I don't understand the rules here. Are we meant to look row by row? If so, doesn't the 5th row count as well (as there is a 0 after the 1)?
Réponse acceptée
Bruno Luong
le 4 Oct 2018
Modifié(e) : Bruno Luong
le 4 Oct 2018
Change the last line to make it can handle with single row:
m = size(h,1);
d = diff(h,1,2);
[r,c] = find(d==-1);
b = sum(abs(d),2)==1;
s = accumarray(r(:),c(:),[m 1]).*double(b)
This because find() rotates the result for row input array.
Plus de réponses (4)
Sean de Wolski
le 3 Oct 2018
h = [1 0 0;
1 1 0;
0 0 1;
1 1 1;
0 1 0];
s = sum(h, 2).*~h(:,end)
requiring the last element to be zero. This wouldn't work for [1 0 1] but I don't know what you'd want for that.
0 commentaires
yp78
le 3 Oct 2018
Modifié(e) : yp78
le 3 Oct 2018
2 commentaires
Sean de Wolski
le 3 Oct 2018
In that case what I have above should work. It returns the sum and requires that the last element be a zero. If the last element is non-zero, it returns a zero.
With [1 0 1] it would say zero because the last element is not a zero.
Bruno Luong
le 4 Oct 2018
Modifié(e) : Bruno Luong
le 4 Oct 2018
h = [1 0 0;
1 1 0;
0 0 1;
1 1 1;
0 1 0];
[a,c] = max(1-h,[],2);
s = (c-1).*a.*h(:,1)
3 commentaires
Bruno Luong
le 4 Oct 2018
Modifié(e) : Bruno Luong
le 4 Oct 2018
Can you explain why it returns 0? Still not clear the rule...
Do you only count only if the row is composing a sequence of 1s followed by a sequence of 0s (of at least one 0)?
Bruno Luong
le 4 Oct 2018
Modifié(e) : Bruno Luong
le 4 Oct 2018
m = size(h,1);
d = diff(h,1,2);
[r,c] = find(d==-1);
b = sum(abs(d),2)==1;
s = accumarray(r(:),c(:),[m 1]).*double(b)
4 commentaires
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