Can someone help me please?
x = 10*ones((10^7),1);
L = ((length(x)*2):-2:2)';
M = x.*L;
p= -M./L;
c= 0.25;
x = x+c*p;
Is possible vectorize x = x+c*p;

5 commentaires

Stephen23
Stephen23 le 8 Oct 2018
Modifié(e) : Stephen23 le 8 Oct 2018
What does "Is possible vectorize x = x+c*p" mean? That line of code already operates on vectors (of appropriate sizes) and does not throw an error. What are you trying to achieve?
Iori Yagami Kusanagi
Iori Yagami Kusanagi le 8 Oct 2018
When I change the value of c, implementing linear search, takes a lot of time this procedure.
Bruno Luong
Bruno Luong le 8 Oct 2018
Modifié(e) : Bruno Luong le 8 Oct 2018
Are you awared that you creates arrays of few hundred of Tb?
Iori Yagami Kusanagi
Iori Yagami Kusanagi le 8 Oct 2018
Yes, is a optimization problem that I need to solve, and when run on that part take a lot of time
Bruno Luong
Bruno Luong le 9 Oct 2018
Modifié(e) : Bruno Luong le 9 Oct 2018
You know how much memory has your PC? Usually few or few dozen Gb. How you intend to carry out the storage of such matrix on the computer?

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Réponses (1)

Jan
Jan le 9 Oct 2018

0 votes

The code works vectorized already. So the problem is not vectorizing.
The code can be simplified slightly:
M = x .* L;
p = -x; % instead of: -M ./ L, but p is not needed at all
c = 0.25;
x = (1-c) * x; % instead of: x + c * p;
The code is not meaningful yet. Maybe there is another way to improve it. But again, vectorization is applied here already.

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