gamma function for N>100
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Ladan Avazpour
le 8 Oct 2018
Commenté : Ladan Avazpour
le 9 Oct 2018
Hi, everyone.
I have written a simple code by using a gamma function. when I choose N>98, the answer is Nan. What should I do to fix this problem?
function sii = diagonals(n, al, alp, bet)
ssi = zeros(1,n+1);
for i = 1:n+1
sii(i) = (2^(al+1)*(gamma(i-1+alp+1))*(gamma(i-1+bet+1)))/((2*(i-1)+al+1)*(factorial(i-1))^2);
end
end
2 commentaires
John D'Errico
le 8 Oct 2018
Modifié(e) : John D'Errico
le 8 Oct 2018
Is there a good reason why you have not just used gamma itself? Why would you write your own poor code to compute something that is computed well already for you? I'm not going to try to decrypt what you are doing based on undocumented, poorly written code. Perhaps you are trying to write your own incomplete gamma. Oops, also exists already, part of MATLAB.
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Walter Roberson
le 9 Oct 2018
If gammaln cannot be made to suit your purpose then you should use the symbolic toolbox or equivalent
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John D'Errico
le 8 Oct 2018
No. You will not make it work for large values, when they exceed the limits of gamma itself. Your code is not better than what you will find inside gamma itself. Sorry, but NOT.
Instead, consider using the function gammaln, the natural log of the gamma function. In essentially all cases when gamma produces an overflow, gammaln will be the solution, by re-writing what you are doing to accommodate logs. Only consider exponentiating at the end.
gammaln(10000)
ans =
82099.7174964424
Those big numbers are meaningless in a double precision context, because they would vastly overflow the dynamic range of a double precision number.
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