How do i filter out certain values in a cell matrix using conditions for strings ?

I have a cell matrix-
x = { 1 2 'a' 'q' ; 2 3 'a' 'p'; 3 4 'a' 'q'; 5 6 'b' 'p' ; 7 8 'b' 'q' ;9 8 'b' 'q';};
or x =
1 2 a q
2 3 a p
3 4 a q
5 6 b p
7 8 b q
9 8 b q
I want to filter out all rows that have 'a' in the 3rd column and 'q' in the fourth. My result matrix should be-
result=
1 2 a q
3 4 a q
How do I do this?

 Réponse acceptée

ANKUR KUMAR
ANKUR KUMAR le 10 Oct 2018
Modifié(e) : ANKUR KUMAR le 10 Oct 2018
You can use contains to find the required letter. contains gives true if the part of search string contains in the main string.
x(contains(x(:,3),'a') & contains(x(:,4),'q'),(3:4))
Better to use strcmp, as it check for complete string. strcmp checks for the complete strings. It gives true only when the complete string is present.
x(strcmp(x(:,3),'a') & strcmp(x(:,4),'q'),(3:4))

3 commentaires

What if my strings were present in say 3rd and 6th columns, then how would I use strcmp? I don't understand the usage of " ,(3:4) " at the end in the expression you gave.
"(3:4) " is used because you wish to extract 3rd and fourth column as output. If you wish all, then use
x(strcmp(x(:,3),'a') & strcmp(x(:,4),'q'),:)
ans =
2×4 cell array
[1] [2] 'a' 'q'
[3] [4] 'a' 'q'
If data is on 3rd and 6th column, then use
x(strcmp(x(:,3),'a') & strcmp(x(:,6),'q'),:)
The above one gives output for complete columns.
For more clarification, refer this,
x = { 1 2 'a' 6 8 'q' ; 2 3 'a' 2 5 'p'; 3 4 'a' 2 1 'q'; 5 6 'b' 1 2 'p' ; 7 8 'b' 1 1 'q' ;9 8 'b' 1 1 'q';}
x =
6×6 cell array
[1] [2] 'a' [6] [8] 'q'
[2] [3] 'a' [2] [5] 'p'
[3] [4] 'a' [2] [1] 'q'
[5] [6] 'b' [1] [2] 'p'
[7] [8] 'b' [1] [1] 'q'
[9] [8] 'b' [1] [1] 'q'
1)
x(strcmp(x(:,3),'a') & strcmp(x(:,6),'q'),:)
ans =
2×6 cell array
[1] [2] 'a' [6] [8] 'q'
[3] [4] 'a' [2] [1] 'q'
2)
x(strcmp(x(:,3),'a') & strcmp(x(:,6),'q'),[3,6])
ans =
2×2 cell array
'a' 'q'
'a' 'q'

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