Frequency of data occurrence using histc

4 vues (au cours des 30 derniers jours)
Edward Jahoda
Edward Jahoda le 10 Oct 2018
Commenté : Megan le 18 Oct 2019
I have a matrix called data which is 40*40*50 and I want to find all the distinct numbers in the matrix and count their occurrences. This code below seems to work when data is 40*40*39 or smaller, but as soon as I try to run the code on the entire data matrix it starts giving 0.001 as the frequency for all of the unique occurrences
% code
out = [unique(data),histc(data(:),a)]
plot(a, histc(data(:),a));
I know that using histc is not recommended, but it was the easiest way I could find to do this.
Thanks for any and all help.

Réponses (2)

Guillaume
Guillaume le 10 Oct 2018
I presume that your numbers are integer (otherwise, you're playing dangerous games using unique with floating point values), in which case:
out = histcounts(data, 'BinMethod', 'integers');
  2 commentaires
Edward Jahoda
Edward Jahoda le 10 Oct 2018
Thanks for the response. I am using floating point values (with 6 values after the decimal point), and consequently wondering if you have some suggestion as to how to deal with the floating points or some information on why its dangerous.
Guillaume
Guillaume le 10 Oct 2018
"some information on why its dangerous"
See the output of
unique([0.3, 0.1+0.1+0.1])
If you want 6 digits of precision, I would do this:
out = histcounts(floor(data * 1e6), 'BinMethod', 'integers');
to move back to integer bins.

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Bruno Luong
Bruno Luong le 10 Oct 2018
You might take a look at uniquetol()

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