Converting double array to struct array for generalized inverse kinematics

5 vues (au cours des 30 derniers jours)
Joo Lee
Joo Lee le 12 Oct 2018
Hello,
q0 = robot.homeConfiguration.JointPosition;
numWaypoints = 5;
qWaypoints = repmat(q0, numWaypoints, 1);
gik = robotics.GeneralizedInverseKinematics;
gik.RigidBodyTree = robot;
gik.ConstraintInputs = {'position'};
posTgt = robotics.PositionTarget(ee);
posTgt.TargetPosition = [1 1 1];
qWaypoints(1,:)= q0;
for k = 2:numWaypoints
[qWaypoints(k,:),solutionInfo] = gik(qWaypoints(:,k-1), posTgt);
end
above is the code that I am working with. The error ouccurs at "gik(qWaypoints(:,k-1), posTgt)". So basically I need to convert the qWaypoints to struct array (currently it is an array of doubles). Is there an easy and simple way for this conversion ?
  2 commentaires
Kevin Chng
Kevin Chng le 12 Oct 2018
Hi,
I guess you have to
convert it to cell first
a=num2cell(gWaypoints);
later, use cell2struc() convert it to structure array.
I don't know how your qWaypoints array looks like, therefore i unable to help you to code it, however, you may refer to documentation :
Walter Roberson
Walter Roberson le 12 Oct 2018
Perhaps just set the robot DataFormat property to 'row'?

Connectez-vous pour commenter.

Réponses (1)

Sebastian Castro
Sebastian Castro le 4 Nov 2018
Instead of converting back and forth, it's easier to stick to a consistent format -- either all structs or all numeric.
If you do either of the following,
robot.DataFormat = 'row';
robot.DataFormat = 'column';
then the robot configuration, including the solution of gik, will be a numeric row/column instead of a struct.
As an alternative, as you said, you can keep everything as a struct. You can simply your first line to
q0 = robot.homeConfiguration
Then, repmat should handle the rest for initializing the array to be of structs rather than numeric.
Finally, your loop contents should become something like:
[qWaypoints(k),solutionInfo] = gik(qWaypoints(k-1), posTgt);
- Sebastian

Catégories

En savoir plus sur Data Type Conversion dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by