Fastest way to create N by 1 matrix which contain lots of zero without using for loop

1 vue (au cours des 30 derniers jours)
I want to express n x 1 matrix, X
X = [ a; a; a; a; b; 0; 0; 0; b; 0; 0; 0; (...) b; 0; 0; 0; b; 0; 0; 0; c; c; ] ("b; 0; 0; 0;" block is repeated N times)
What I first design is that:
A = a * ones(4,1) ; B = zeros(4,1); B(1) = b ; C = c * ones(2,1); X = [ A ; B ; B ; (...) B ; B ; C ] ;
But the problem is that I cannot set a number of center block. How can I code it?
Thanks in advance :D

Réponse acceptée

OCDER
OCDER le 12 Oct 2018
a = 1;
b = 2;
c = 3;
N = 10;
D = [repelem(a, 4, 1);
repmat([b; 0; 0; 0], N, 1);
repelem(c, 2, 1)];

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by