sphere with center and radius
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how to plot a sphere with center(6500000,6500000,6500000) and radius 650000
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Image Analyst
le 15 Oct 2018
Try this:
% Make unit sphere
[x,y,z] = sphere;
% Scale to desire radius.
radius = 650000;
x = x * radius;
y = y * radius;
z = z * radius;
% Translate sphere to new location.
offset = 6500000;
% Plot as surface.
surf(x+offset,y+offset,z+offset)
% Label axes.
xlabel('X', 'FontSize', 20);
ylabel('Y', 'FontSize', 20);
zlabel('Z', 'FontSize', 20);
axis equal;

8 commentaires
GEORGIOS TSAKIRAKIS
le 16 Oct 2018
Ravi Singh
le 3 Mar 2020
Hii Image Analyst,
i have drawn the sphere from the given coordinates and radius , now i want to check the pixel value of color map so that i can verify if some pixels are present inside the sphere or not .
Image Analyst
le 3 Mar 2020
Just check the distance from the offset or center
distance = sqrt((x-xCenter).^2+(y-yCenter).^2+(z-zCenter).^2);
if distance is less than the radius, it's inside.
M.S. Khan
le 2 Avr 2020
Hi Image Analyst, could you please explain, what is xCenter?
Image Analyst
le 21 Nov 2021
@M.S. Khan xCenter is the x location of the center of the sphere. For the example I gave it's 6500000.
@Jeson Lonappan, you can't get them from this. It's not the earth. And there is mo Merdian line defined so there is no absolute longitude. Any point on the sphere could therefore be any longitude.
Alberto Acri
le 24 Jan 2024
Modifié(e) : Alberto Acri
le 24 Jan 2024
Hi @Image Analyst! How can I extract the coordinates of the sphere nodes? The x,y,z matrices are 21x21 doubles. I would like to use plot3!
Image Analyst
le 24 Jan 2024
I don't know from that function, but you can of course easily generate your own coordinates on the shell of the sphere. For any given z value, it's simply a circle. See the FAQ:
DGM
le 24 Jan 2024
See also:
That is one way to use plot3() to draw a spherical shell. Once you have the x,y,z data, you can offset it to the desired center.
If it's not actually necessary to use plot3() specifically, or if the sphere needs to be drawn in some other manner, then you'll have to say.
Ankita De
le 11 Juil 2022
0 votes
can you please tell nearest neighbour and contact distance distribution using binomial point process
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