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Why i get the out of bound error in this code?

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IBM watson
IBM watson on 21 Oct 2018
Commented: IBM watson on 21 Oct 2018
myset=[1 2 3 4 6];
capacity=6;
passedall=[]
passed=[]
for q = 1:5
    q=q+1
    capacity=6;
    passedall = [passedall passed]; 
    myset= setdiff(myset,passedall);
    for b= 1:5
      if (myset(b) < capacity);
        capacity= capacity - myset(b)
        passed(b) = myset(b)
      end
    end
  end

i get this error:

error: myset(4): out of bound 3
error: called from
    deneme at line 13 column 5

  2 Comments

madhan ravi
madhan ravi on 21 Oct 2018
passedall = [passedall passed]
doesn't have any values ?

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Accepted Answer

Guillaume
Guillaume on 21 Oct 2018
Why i get the out of bound error in this code
Because by the time b equals 4, you've removed enough elements from myset that there are only 3 left and myset(b) is no longer valid. Have you tried debugging your program?
I have no idea what you're trying to do with your code since it's not commented at all. As it is, it doesn't make any sense and probably your loops are not needed. Without an explanation of what you're trying to achieve we can't tell you how to fix it.
Note that
for q = 1:5
q=q+1
has exactly the same effect as
for q=2:6

  1 Comment

IBM watson
IBM watson on 21 Oct 2018
"Because by the time b equals 4, you've removed enough elements from myset that there are only 3 left and myset(b) is no longer valid."
This!! Thank you.

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