Effacer les filtres
Effacer les filtres

How do i count same consecutive occurrences

29 vues (au cours des 30 derniers jours)
DuckDuck
DuckDuck le 23 Oct 2018
Commenté : Bruno Luong le 16 Déc 2021
Consider I have an array of occurrences
A=[1,1,1,1,1,2,2,2,2,3,3,3,3,2,2,2,1,1,1,1]
I want to find out how many 2 are on each occurrence. The answer should be 4 starting 6th position and 3 starting 14 positions.
Is it possible to do it in a wise Matlab way without many loop complications?

Réponses (3)

madhan ravi
madhan ravi le 23 Oct 2018
Modifié(e) : madhan ravi le 23 Oct 2018

Daniel Pare
Daniel Pare le 5 Nov 2019
I wanted to count how many time in a row Head or Tail will occure from a random draw and I came up with this.
Let (x) be your vector of observation like x = [1 1 0 1 0 0 0 1]
The result will be: s = [ 2 1 1 3 1]
s=0 ;
j=2;
i=1;
while i < nb_it+1
c=1;
if i == nb_it
s = [ s c];
break
else
while x(i) == x(i+1)
c = c+1;
i = i+1;
if i == nb_it
break
end
end
end
s = [ s c];
i = i+1;
end
s = s(2:end); % to remove the first zero
sum(s) % the sum should be equal to the number of element in (x)
max(s) % This is the maximum of consecutive ocurence from the draw
  5 commentaires
giannit
giannit le 23 Avr 2020
That one line command is amazing, many thanks!
gummiyummi
gummiyummi le 3 Août 2020
I get an error: Error using horzcat. Dimensions of arrays being concatenated are not consistent.
Can anybody help resolve this?

Connectez-vous pour commenter.


Bruno Luong
Bruno Luong le 3 Août 2020
Modifié(e) : Bruno Luong le 16 Déc 2021
Example:
A=[1,1,1,1,1,2,2,2,2,3,3,3,3,2,2,2,1,1,1,1]
Code
d = diff([0, A==2, 0]);
startidx = find(d==1)
lgt = find(d==-1)-startidx % EDIT error
Result
startidx =
6 14
lgt =
4 3
  4 commentaires
Ayush Meena
Ayush Meena le 15 Déc 2021
@Bruno can you please tell me what is idx here?
Bruno Luong
Bruno Luong le 16 Déc 2021
@Ayush Meena it's a typo, should be startidx.

Connectez-vous pour commenter.

Catégories

En savoir plus sur MATLAB dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by