Subscript indices must either be real positive integers or logicals.

2 vues (au cours des 30 derniers jours)
alireza kooshafar
alireza kooshafar le 25 Oct 2018
i got this error in this code i don't know why.
c=[x(1:end-1,:),x(2:end,:)];
dx=c(:,2)-c(:,1);
t=[y(1:end-1,:),y(2:end,:)];
dy=t(:,2)-t(:,1);
ra=[];
rb=[];
for i=1:size(dx)
if dx(2i-1)>0 & dy(2i)<0;
ra(2i-1)=1;
ra(2i)=1;
end
if dy(2i-1)>0 & dx(2i)<0;
rb(2i-1)=1;
rb(2i)=1;
end
end
  1 commentaire
Adam
Adam le 25 Oct 2018
Which line is the error on? You can use the stop/pause on errors debug option from the Breakpoints menu to have the code stop at the line causing the error. Then it is trivial to work out what is wrong by looking at any subscript indices you are using in the command window.

Connectez-vous pour commenter.

Réponse acceptée

jonas
jonas le 25 Oct 2018
Modifié(e) : jonas le 25 Oct 2018
It's hard to tell without having some input, but these types of lines are definitely wrong:
ra(2i)=1;
i is being interpreted as imaginary, which is why you should not use i as a looping variable.
ans =
0.0000 + 2.0000i
Could be other errors as well.
  6 commentaires
alireza kooshafar
alireza kooshafar le 25 Oct 2018
I have two matrices(dx dy), I'm looking for a condition to check 1. If the first array of dx was a positive (negative), the first array of dy be a negative (positive) array. 2. If the event is the first one, check if the odd arrays of dx and dy will all be the same and the even arrays are exactly the opposite.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by