Following code is coming up with error "Array indices must be positive integers or logical values."
Does someone know what is causing this. Trying to store each value into an array
z =@(x) tan(x);
h = 0.5
for x=1:0.5:10
Output (x) = (z(x+h)-z(x-h))/(2*h);
end
Array = [Output]

1 commentaire

Stephen23
Stephen23 le 25 Oct 2018
Modifié(e) : Stephen23 le 25 Oct 2018
Note that your code can be trivially vectorized (a loop is a waste of time):
z = @tan;
h = 0.5;
x = 1:0.5:10;
y = (z(x+h)-z(x-h))./(2*h);
Learn how to write neat and efficient MATLAB code:

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 Réponse acceptée

madhan ravi
madhan ravi le 25 Oct 2018
Modifié(e) : madhan ravi le 25 Oct 2018

0 votes

z =@(x) tan(x);
h = 0.5
x=1:0.5:10
Output = zeros(1,19) %preallocation for speed and efficiency
for i = 1:numel(x)
Output (i) = (z(x(i)+h)-z(x(i)-h))/(2*h);
end
Array = Output

3 commentaires

madhan ravi
madhan ravi le 25 Oct 2018
you can access x(1.5)->(second iteration) because indexing should be real integers
Stephen23
Stephen23 le 25 Oct 2018
@madhan ravi: where is the array preallocation? What do those square brackets do? (Hint: nothing)
madhan ravi
madhan ravi le 25 Oct 2018
Thank you Stephen (edited now)

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