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element by element sum with two arrays

14 vues (au cours des 30 derniers jours)
Adam Parry
Adam Parry le 3 Juil 2012
I basicly have to arrays A1 and B1 and would like to do this
sum(over i)((A1(i)-a*B1(i)-b)^2)
so i tried using this
sum((A1-a*B1-b).^2)
but that does not do it element by element
any hints?
a and b are constants
  1 commentaire
Kye Taylor
Kye Taylor le 3 Juil 2012
Can you provide concrete values for a,b,A1,B1 as @Thomas does above? Can you also give/describe the output that you're looking for?

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Réponses (1)

Thomas
Thomas le 3 Juil 2012
Is this how you want it..
A1=[1:4];
B1=[5:8];
a=2;
b=2;
c=(A1-a.*(B1-b)).^2 % just to show the element wise subtract and square
sum(c)
  2 commentaires
Adam Parry
Adam Parry le 4 Juil 2012
I don't think that is quite right.
C = (A1-(a*B1)-b).^2
but will it still give me the correct element wise sum?
Ryan
Ryan le 4 Juil 2012
Modifié(e) : Ryan le 4 Juil 2012
Thomas did misplace a parentheses.
What is in your original post should do exactly what you asked it to do. By using "sum()" you are summing up all of the components of the vector thus resulting in a singular result. If that is not what you'd like, then you should try adding more detail and writing out your problem statement as clear as possible so we can try to help.

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