comparing matices that contain numbers and NaNs
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I have 2 cell matrices R and W and I want to check if they contain the same elements. Specifically, I want to compare R which is obtained from
[N,T,R] = xlsread( filename); %
with another matrix W.Both matrices are cell matrices and can also contain NaN entries.
My goal: If my calculations are correct then
kk=W(7 ,3:end); should contain the same elements with
zz1=R(7,3:end);
or zz2=R(8,3:end);
So to test this I do something like
if zz==xx1 | zz== xx2
'OK' else 'Not OK' EndThe problem is that
zz==xx1
??? Undefined function or method 'eq' for input arguments of type 'cell'.
So I use cell2mat(zz)==cell2mat(xx1) and it works.
But if zz and xx1 contain NaN then for some reason I cannot use the cell2mat() approach
I am looking for a general approach that will enable me to do that comparison whether I have NaN and numbers or only numbers’
thanks
1 commentaire
Jan
le 5 Juil 2012
@Readers: It seems like anonet wants to compare cells, which contain numerical and string values.
Réponse acceptée
Plus de réponses (2)
Jan
le 5 Juil 2012
C1 = {'String1', 23, -17, NaN, 1:29);
C2 = {'String2', 24, -17.3, 21, 1:30);
C3 = {'String1', 23, -17, NaN, 1:29);
% |C1==C2| fails!
isequalwithequalnans(C1, C2)
isequalwithequalnans(C1, C3)
I cannot test this currently. When NaNs should be assumed to be different, isequal would do it.
4 commentaires
antonet
le 5 Juil 2012
Andrei Bobrov
le 5 Juil 2012
+1
Teja Muppirala
le 5 Juil 2012
On more recent releases, there is the ISEQUALN function so you don't have to write out ISEQUALWITHEQUALNANS
antonet
le 5 Juil 2012
Kevin Claytor
le 4 Juil 2012
0 votes
My guess from searching the help docs for 'cell' gives;
m = cell2mat(c) converts a multidimensional cell array c with contents of the same data type into a single matrix, m.
3 commentaires
antonet
le 4 Juil 2012
Walter Roberson
le 5 Juil 2012
What do you want to have happen in the locations that contain strings? It is not possible for a numeric array to contain strings.
Jan
le 5 Juil 2012
@antonet: Please provide the necessary information in the original question, because readers in this forum will read it at first. Therefore you can edit the question.
The code you have posted is hard to read. Please read the instructions about code formatting again.
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