X =
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
and Y=
1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
1.2000 1.2000 1.2000 1.2000 1.2000 1.2000
1.4000 1.4000 1.4000 1.4000 1.4000 1.4000
1.6000 1.6000 1.6000 1.6000 1.6000 1.6000
1.8000 1.8000 1.8000 1.8000 1.8000 1.8000
2.0000 2.0000 2.0000 2.0000 2.0000 2.0000
and i need an n*2 matrix by pairing up corresponding elements of each of the matrices x and y. the
ex [ 1 1; 1.2 1; 1.4 1; 1.6 1; 1.8 1; 2 1; 1 1.2; 1.2 1.2;...............] and so on

 Réponse acceptée

Stephan
Stephan le 6 Nov 2018

0 votes

x = [1 2; 3 4]
y = [5 6; 7 8]
z = [x(:) y(:)]

3 commentaires

For bigger matrices, it gives away only the diagonal elements
Stephan
Stephan le 6 Nov 2018
Modifié(e) : Stephan le 6 Nov 2018
No, see this example:
x = reshape(1:25,5,5)
y = reshape(26:50,5,5)
z = [x(:) y(:)]
result:
x =
1 6 11 16 21
2 7 12 17 22
3 8 13 18 23
4 9 14 19 24
5 10 15 20 25
y =
26 31 36 41 46
27 32 37 42 47
28 33 38 43 48
29 34 39 44 49
30 35 40 45 50
z =
1 26
2 27
3 28
4 29
5 30
6 31
7 32
8 33
9 34
10 35
11 36
12 37
13 38
14 39
15 40
16 41
17 42
18 43
19 44
20 45
21 46
22 47
23 48
24 49
25 50
Diagonal values would be 5 pairs - this are 25 pairs of values. I think this is what you expected - isnt it?
yeah , your right.

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