i have two martices

3 vues (au cours des 30 derniers jours)
Bhavana Chinnabalannagari
X =
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
and Y=
1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
1.2000 1.2000 1.2000 1.2000 1.2000 1.2000
1.4000 1.4000 1.4000 1.4000 1.4000 1.4000
1.6000 1.6000 1.6000 1.6000 1.6000 1.6000
1.8000 1.8000 1.8000 1.8000 1.8000 1.8000
2.0000 2.0000 2.0000 2.0000 2.0000 2.0000
and i need an n*2 matrix by pairing up corresponding elements of each of the matrices x and y. the
ex [ 1 1; 1.2 1; 1.4 1; 1.6 1; 1.8 1; 2 1; 1 1.2; 1.2 1.2;...............] and so on

Réponse acceptée

Stephan
Stephan le 6 Nov 2018
x = [1 2; 3 4]
y = [5 6; 7 8]
z = [x(:) y(:)]
  3 commentaires
Stephan
Stephan le 6 Nov 2018
Modifié(e) : Stephan le 6 Nov 2018
No, see this example:
x = reshape(1:25,5,5)
y = reshape(26:50,5,5)
z = [x(:) y(:)]
result:
x =
1 6 11 16 21
2 7 12 17 22
3 8 13 18 23
4 9 14 19 24
5 10 15 20 25
y =
26 31 36 41 46
27 32 37 42 47
28 33 38 43 48
29 34 39 44 49
30 35 40 45 50
z =
1 26
2 27
3 28
4 29
5 30
6 31
7 32
8 33
9 34
10 35
11 36
12 37
13 38
14 39
15 40
16 41
17 42
18 43
19 44
20 45
21 46
22 47
23 48
24 49
25 50
Diagonal values would be 5 pairs - this are 25 pairs of values. I think this is what you expected - isnt it?
Bhavana Chinnabalannagari
yeah , your right.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Operating on Diagonal Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by