Need the row of an array that gives minimum value if we sum all the elements of the row in a matrix?

clear all
clc

% S(j)= sum of sub illuminance induced by each luminaire (illuminance produced on jth location)
% m = number of luminaires
% n = number of preferred illuminance
% li(j)= largest illuminance of jth location induced only by ith luminaire i = no of luminaires, j = locations )
% Let us consider L matrix

L= [90 106 25 51 56 19 18 18 11 7 9 7; 
    20 91 114 17 51 59 11 18 20 6 9 9;
    9 37 158 8 27 75 6 8 23 5 8 9;
    79 35 9 133 42 8 47 23 6 16 8 5;
    8 28 80 8 30 127 5 18 46 5 7 8;
    7 18 34 7 27 95 7 27 103 5 14 34;
    11 15 17 14 32 36 17 74 91 16 58 65;
    6 12 18 7 19 43 7 29 124 7 28 38]

x=max(L(3,:))
% T=rand(1,12)

Llt=100;
Ult=350;

Se=Llt+(Ult-Llt).*rand(8,1)
res=[];
TT=[];

for i=1:10000

T(i,:)=rand(1,12);
end
for j=1:10000
Scc=L*T(j,:)';

b=Scc>=Se;
if b==ones(8,1)
TT=[TT;T(j,:)];
ff=j
end
end
A=size(TT)
mm=A(1)
nn=A(2)
for l=1:A(1)
    s(l,:)=sum(TT(l,:));
end
xx=min(s)        

% Need the row of 'TT' that gives minimum of 's'

[madhan ravi]

edit your code properly so that its easy to read

[sarath yadav]

edited sir

[madhan ravi]

see my answer below

[Guillaume]

I'm not sure why the code is relevant to the question. I've not tried to understand as it looks more complicated than it needs. First things, I've spotted:

for i=1:10000
   T(i,:)=rand(1,12);
end

is simply

T = rand(10000, 12);

and

A=size(TT)
for l=1:A(1)
    s(l,:)=sum(TT(l,:));
end

is simply

s = sum(TT, 2);

and

b=Scc>=Se;
if b==ones(8,1)

is simply

b=Scc>=Se;
if all(b)

[sarath yadav]

@Guillaume

Thanks for your suggestions sir

Answer 1

[madhan ravi]

[~,xx]=min(s) 
TT(xx,:) %row for minimum value of s

[sarath yadav]

Thank you sir..

[madhan ravi]

Anytime :) also consider Guillaume’s comment which makes your code really efficient