How made the code as easy?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
P=[1 32 3 78 5 6 7 8 9 10] ;P is my original array which has the size is 1*10; I have Q=[2 4 7];I want delete in Q array value in P array; My expect output is P=[ 1 3 5 6 8 9 10] by using for loop only because of the size of Q array may be change ;P(:,[Q(1) Q(2) Q(3)])=[] this command use only the size of Q array is 1*3 .So I need for loop logic which is common of any array size.
0 commentaires
Réponse acceptée
madhan ravi
le 8 Nov 2018
Modifié(e) : madhan ravi
le 8 Nov 2018
P(Q)=[] %edited after Jan's comment
13 commentaires
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!