How can I draw these rectangles in a loop using psychtoolbox... there must be a better way than what I've done. Thanks for your help!!
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Olivia Krieger
le 8 Nov 2018
Commenté : Olivia Krieger
le 8 Nov 2018
% Draw base rectangle
r1=[0 0 20 20];
r2=OffsetRect(r1, 200,200);
r3=OffsetRect(r1, 200,235);
r4=OffsetRect(r1, 235,200);
r5=OffsetRect(r1, 235,235);
r6=OffsetRect(r1, 300,235);
r7=OffsetRect(r1, 300,200);
r8=OffsetRect(r1, 335,200);
r9=OffsetRect(r1, 335,235);
r10=OffsetRect(r1, 200,100);
r11=OffsetRect(r1, 200,135);
r12=OffsetRect(r1, 235,100);
r13=OffsetRect(r1, 235,135);
r14=OffsetRect(r1, 300,100);
r15=OffsetRect(r1, 300,135);
r16=OffsetRect(r1, 335,100);
r17=OffsetRect(r1, 335,135);
Screen('FillRect',win, [0, 0, 1], r2);
Screen('FillRect',win, [0, 0, 1], r3);
Screen('FillRect',win, [0, 0, 1], r4);
Screen('FillRect',win, [0, 0, 1], r5);
Screen('FillRect',win, [0, 0, 1], r6);
Screen('FillRect',win, [0, 0, 1], r7);
Screen('FillRect',win, [0, 0, 1], r8);
Screen('FillRect',win, [0, 0, 1], r9);
Screen('FillRect',win, [0, 0, 1], r10);
Screen('FillRect',win, [0, 0, 1], r11);
Screen('FillRect',win, [0, 0, 1], r12);
Screen('FillRect',win, [0, 0, 1], r13);
Screen('FillRect',win, [0, 0, 1], r14);
Screen('FillRect',win, [0, 0, 1], r15);
Screen('FillRect',win, [0, 0, 1], r16);
Screen('FillRect',win, [0, 0, 1], r17);
% Show it on the display:
Screen('Flip', win);
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Jeff Miller
le 8 Nov 2018
One simple improvement is to make r a cell array. Add a command at the top like
r=cell(17,1);
Then, instead of commands like
r2=OffsetRect(r1, 200,200);
you would use
r{2}=OffsetRect(r{1}, 200,200);
Then, at the end, you could draw all the rectangles with 3 lines:
for i=2:17
Screen('FillRect',win, [0, 0, 1], r{i});
end
Screen('flip');
I'm sure you could do even better by working out a pattern to compute the various values of r, 2-17, but I'm not sure that would be worth the effort.
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Olivia Krieger
le 8 Nov 2018
2 commentaires
Jeff Miller
le 8 Nov 2018
There would be be many different ways to do this, and it is tough to say which one will be most convenient without studying your full pattern in detail. But you will probably want to use some kind of loop like this:
for i=2:17
newx = ???; % compute values here depending on your pattern.
newy = ???; % You will need 'if' statements if the values depend on i.
r{i}=OffsetRect(r1, newx,newy);
end
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