Using vectors to all points on a meshgrid

I have a meshgrid across x y and z and need to produce vectors from the origin to all points in the meshgrid that can be used in an potential equation to find the potential at each point as from the origin. How would I go about doing this?
[X Y Z] = meshgrid((-4.05:0.1:4.05),(-4.05:0.1:4.05),(-4:0.1:4))

5 commentaires

jonas
jonas le 10 Nov 2018
What do you mean vectors? X Y Z already have the coordinates for each point and the other point is obviously [0 0 0]. What is the desired format?
James
James le 10 Nov 2018
I am using an equation that has vector r in to find the potential. I am trying to use this equation for all values of the vector r from [0 0 0] so I can essentially have a array containing all values of potential for each point.
James
James le 10 Nov 2018
Modifié(e) : madhan ravi le 10 Nov 2018
Adding on sorry, the problem I am having is that I dont know how to have this vector go across all values.
k*(dot(p,R))./rpo.^2 - k*(dot(p,R))./rne.^2;
The only bit I need help with is R, how do I define R so that is goes across all values?
Walter Roberson
Walter Roberson le 10 Nov 2018
dot() as a call does not vectorize. For real valued vectors, dot = sum(x.*y) which can be extended to arrays if you are careful about shapes and directions and replication. In some cases you can use the * operator after having arranged the right orientation.
"dot() as a call does not vectorize."
Not true:
>> y=rand(3,4)
y =
0.751267059305653 0.699076722656686 0.547215529963803 0.257508254123736
0.255095115459269 0.890903252535798 0.138624442828679 0.840717255983663
0.505957051665142 0.959291425205444 0.149294005559057 0.254282178971531
>> x=rand(size(y))
x =
0.814284826068816 0.349983765984809 0.616044676146639 0.830828627896291
0.243524968724989 0.196595250431208 0.473288848902729 0.585264091152724
0.929263623187228 0.251083857976031 0.351659507062997 0.549723608291140
>> dot(x,y)
ans =
1.144034879739528 0.660675444113866 0.455219273317489 0.845771767133647

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le 10 Nov 2018

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