For loop: Odd numbers turn 0 when checked if even

Hello,

Sorry if the title is misleading. In short, when code checks if number is even; it assigns it to evens. However, if number is odd; it turns it into 0 and assigns it to even.

Here is the output...

48 55 6 66 89 11 44 29 99 61 26 14 55 83 84 84 21 55 88 13

48 0 6 66 0 0 44 0 0 0 26 14 0 0 84 84 0 0 88

48 is even, 55 is not so it turns into 0, 6 is even, and so on....

integers = randi([1 100], 1, 20);
evens = ones(1);
odds = ones(1); 

for k = 1:length(integers)
    
    if mod(integers(k), 2) == 0  % check if number is even
        evens(k) = integers(k);
    end
    
    odds(k) = integers(k); % else if number is odd
    
end

Answer 1

[KSSV]

integers = randi([1 100], 1, 20);
evens = zeros([],1) ;
odds = zeros([],1) ;
c1 = 0 ;c2 = 0 ;
for k = 1:length(integers)
    
    if mod(integers(k), 2) == 0  % check if number is even
        c1 = c1+1 ;
        evens(c1) = integers(k);
    else
        c2 = c2+1 ;
        odds(c2) = integers(k); % else if number is odd
    end
    
end

YOu need not to use loop even.....you can straight away get what you want.

integers = randi([1 100], 1, 20);
evens = integers(mod(integers,2)==0) ;
odds = integers(mod(integers,2)~=0) ;

[Obadah M.]

Thanks it worked.

What is the explaination behind this?

[KSSV]

YOu have initiliazed your evens/odds to zeros ...and when conditon is met..the zero will be repalced..and where condition is not met..zero remains same. In the given code..I am writitng value only when condition is met.

[Obadah M.]

Alright thanks!