how I do it. the function is called a string is passes a numbr

2 vues (au cours des 30 derniers jours)
Dezdi
Dezdi le 19 Nov 2018
Commenté : dpb le 20 Nov 2018
how could I do this one
looks like
functionname('hello')
ans= hello1
functionname('john')
ans= john2
...
many thanks
  1 commentaire
dpb
dpb le 19 Nov 2018
Which number, in particular? Any one, random, user-specified, sequential since last invocation as shown above (requires some extra logic to keep track of that and over what population if so)...???
So many questions, so little known... :)
s=sprintf('%s%d',str,randi(1000);
might give you some ideas, however...

Connectez-vous pour commenter.

Réponse acceptée

Stephen23
Stephen23 le 20 Nov 2018
function out = myfun(inp)
persistent cnt
if nargin==0 || isempty(cnt)
cnt = 0;
end
cnt = cnt+1;
assert(cnt<=5,'You already have five words')
out = sprintf('%s%d',inp,cnt);
end
And tested:
>> myfun('anna')
ans = anna1
>> myfun('bob')
ans = bob2
>> myfun('cathy')
ans = cathy3
>> myfun('david')
ans = david4
>> myfun('evalyn')
ans = evalyn5
>> myfun('frog')
error: You already have five words
  1 commentaire
Dezdi
Dezdi le 20 Nov 2018
Modifié(e) : Dezdi le 20 Nov 2018
thank you
Is there any way to write message here not just post?

Connectez-vous pour commenter.

Plus de réponses (2)

Luna
Luna le 20 Nov 2018
Hello Dezdi,
You can do it by first collecting your inputs in a cell array and then call your function in a for loop with 5 elements.
inputStr = {'John','Mary','Kayle','Adam','David'};
for i = 1:5
out = myFunc(inputStr,i)
end
function outputStr = myFunc(inputStr,i)
outputStr = [inputStr{i}, sprintf('%d',i)];
end

Preethi
Preethi le 20 Nov 2018
hi,
check this
function test_preethi(str)
persistent i
if isempty(i)
i=1;
else
if i <=5
sprintf('%s%d',str,i)
i=i+1 ;
else
sprintf('limit reached')
end
end
  3 commentaires
Dezdi
Dezdi le 20 Nov 2018
Modifié(e) : Dezdi le 20 Nov 2018
thank you it works for me sorry I am new here can't accept all of you answers.
dpb
dpb le 20 Nov 2018
This particular function only "works" in that it creates the string internal to the function but you can't get at the result.
The use of persistent is good in saving the previous value, unfortunately the function has no mechanism by which the variable can be reset/re-initialized so without external intervention once the sequence is full, there's no going forward...details, details! :)

Connectez-vous pour commenter.

Catégories

En savoir plus sur Characters and Strings dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by