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Why does the output of a discrete transfer function goes NaN?

9 vues (au cours des 30 derniers jours)
Dawn Ivan
Dawn Ivan le 20 Nov 2018
Commenté : Rahul Shinde le 15 Juil 2022
My simulink model has a discrete transfer function block.The numerator and the denominator are given externally because their coefficients change as the simulation runs.What are the possible reasons for the output of the discrete transfer function to go NaN?What are the possible soultions to solve the same?
  3 commentaires
Walter Roberson
Walter Roberson le 14 Juil 2022
You have infinity or negative infinity in the input signal, and you do not happen to have the situation where all non-zero coefficients appear only in even powers.
For example negative infinity and coefficients [1 1 1] would be 1*(-inf)^2 + 1*(-inf) + 1 which would be (inf) + (-inf) + 1 and inf - inf is nan.
Rahul Shinde
Rahul Shinde le 15 Juil 2022
Many thanks for your response @Walter Roberson. After your hints I was able to focus & identify the issue in my model.
Good day.

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