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What does this ODE error mean?

3 vues (au cours des 30 derniers jours)
Tom Keaton
Tom Keaton le 24 Nov 2018
Commenté : Tom Keaton le 24 Nov 2018
Hello,
I don't understand why I am getting the following error:
Error using odearguments (line 87)
The entries in tspan must strictly increase or decrease.
Error in ode15s (line 150)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in trajecttest (line 39)
[T,S] = ode15s(@bdipuniodefun, tspan, icv);
For this for loop:
spart = [0.05 0.05 0.];
vpart = [-1.7585E+7 -1.7585E+7 0.];
tstep = 1E-7; %Defining time step
tfin = 1.1E-6; %Defining final time
intspan = [0:tstep:tfin]; %Total time span
[introw,intcol] = size(intspan);
W = zeros((3*intcol),6); %Generates matrix of zeros that the trajectory solver will populate later
for t = 0:1:intcol/2-1
x = spart(1);
y = spart(2);
z = spart(3);
vx = vpart(1);
vy = vpart(2);
vz = vpart(3);
icv = [x; y; z; vx; vy; vz];
%Time span
tspan = [intspan(2*t+1) intspan(2*t+2)/2 intspan(2*t+2)];
[T,S] = ode15s(@bdipuniodefun, tspan, icv);
[rownum,colnum] = size(S);
W((1+3*t):(3+3*t),(1:6)) = S;
vparts(1) = S(rownum,4);
vparts(2) = S(rownum,5);
vparts(3) = S(rownum,6);
sparts(1) = S(rownum,1);
sparts(2) = S(rownum,2);
sparts(3) = S(rownum,3);
end
The ODE solver accepts the inputs if there is no for loop invovled like this:
x = 0.05;
y = 0.05;
z = 0.;
vx = -1.7585E+7;
vy = -1.7585E+7;
vz = 0.;
tstep = 0.5E-8; %Defining time step
tfin = 1E-8; %Defining final time
intspan = [0:tstep:tfin]; %Total time span
[introw,intcol] = size(intspan);
icv = [x; y; z; vx; vy; vz]; %Format: [x; y; z; vz; vy; vz]
%Time Span (sec)
tspan = [intspan];
[T,W] = ode15s(@bdipuniodefun, tspan, icv);
[rownum,colnum] = size(W);
So why is it that adding the for loop causes this error? I know that the numbers that the "tspan" array is taking in are exactly the same since I tested it in the command window.
  1 commentaire
madhan ravi
madhan ravi le 24 Nov 2018
upload bdipuniodefun

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Stephan
Stephan le 24 Nov 2018
Hi,
the message is clear. See what happens if you inspect some lines of your code - therefore lets assume t=1 which is the second step of your loop in:
for t = 0:1:intcol/2-1
So with t=1 what do we get as tspan?
t = 1
tstep = 1E-7;
tfin = 1.1E-6;
intspan = [0:tstep:tfin];
tspan = [intspan(2.*t+1) intspan(2.*t+2)/2 intspan(2.*t+2)]
And the result is:
tspan =
1.0e-06 *
0.2000 0.1500 0.3000
The error message tells us:
Error using odearguments (line 87)
The entries in tspan must strictly increase or decrease.
Since your values first decrease and then increase you get this error.
Best regards
Stephan
  1 commentaire
Tom Keaton
Tom Keaton le 24 Nov 2018
Thank you!

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