How to: Count length of identical consecutive elements in an array

An earlier answer provided to counting identical consecutive elements in an array is as follows (tabulate command added by me)

X = [0 0 0 0 1 1 1 0 1 1 1 1 0 0]; % Sample data

d= [true, diff(X) ~= 0, true]; % TRUE if values change

n = diff(find(d)); % Number of repetitions

tabulate(n)

This code combines the consecutive element lengths of different elements (0s and 1s) in the answer

--> However, am trying to determine length of consecutive elements of "each element type" (not combine consecutive lengths of different element values)

Output content would be something like:

Array entry 0: consecutive length 4, # of occurences=1

Array entry 0: consecutive length 2, # of occurences=1

Array entry 0: consecutive length 1, # of occurences=1

Array entry 1: consecutive length 4, # of occurences=1

Array entry 1, consecutive length 3, # of occurences=1

[Jay Alan]

The following seems to work; any elegant solutions would be greatly appreciated

rr=[  NaN
       NaN
       NaN
    0.0382
   -0.0211
    0.0252
    0.0165
   -0.0417
   -0.0128
    0.0667
   -0.0040
   -0.0329
   -0.0340
    0.0172
   -0.0085
    0.0128
    0.0210
   -0.0295
   -0.0260
    0.0260]
rr1=rr>0;
b1 = diff([0 rr1' 0] ==1);
c1 = find(b1==-1) - find(b1==1);
tabulate(c1)
%--
rr0=rr<0;
b0 = diff([0 rr0' 0] ==1);
c0 = find(b0==-1) - find(b0==1);
tabulate(c0)

Answer 1

[KSSV]

A =  [0     0     0     0     1     1     1     0     1     1     1     1  0  0]; % Sample data
ii = zeros(size(A));
jj = A > 0;
ii(strfind([0,jj(:)'],[0 1])) = 1;
idx = cumsum(ii).*jj;
out = accumarray( idx(jj)',A(jj)',[],@(x){x'});

Reference: https://in.mathworks.com/matlabcentral/answers/104614-grouping-continuous-nonzero-in-a-row-vector

[Jay Alan]

Thank you very much for the suggestion; am unable to get outputs with your code and will need to analyze further (with my sincere apologies for the delay). Thanks once again.