selecting only the numbers from a string variable
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Dear all,
I have
A={'BARI 500G' ...
'DUR NOR 18CONmS' ...
'SENSO NORM ST-TUB 75ML '...
'MARL 100S 20CIG'...
'BI BOY WHI RMAL DU NA 15 SK'...
'REGU KR GRA ME FAMIAL 1000 ST GRND'
};
I was wondering if there is a way to choose the numbers from A. In case i have 2 numbers in a string I want to select the second one
For instance,
B=[500 18 78 20 15 1000]
5 commentaires
antonet
le 10 Juil 2012
antonet
le 10 Juil 2012
Tom
le 10 Juil 2012
Num = regexp(A,'\d') tells you where the digits are, but you'll have to do some work to make those into numbers- for example '1000' will come up as 4 results are there are 4 digits, even though they make one number
antonet
le 10 Juil 2012
Luffy
le 10 Juil 2012
@Antonet: Do you need those numbers as a vector??
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Plus de réponses (2)
GS76
le 26 Oct 2020
0 votes
To whom it may concern:
I have the numbers below in a 1x1 string. How do I seperate them into seperate rows or columns? I want all the numbers between ";" (semi-colons).
Any assistance would be greatly appreciated.
0.0;0.005;0.01;0.015;0.02;0.025;0.03;0.035;0.04;0.045;0.05;0.055;0.06;0.065;0.07;0.075;0.08;0.085;0.09;0.095;0.1;0.105;0.11;0.115;0.12;0.125;0.13;0.135;0.14;0.145;0.15;0.155;0.16;0.165;0.17;0.175;0.18;0.185;0.19;0.195;0.2;0.205;0.21;0.215;0.22;0.225;0.23;0.235;0.24;0.245;0.25;0.255;0.26;0.265;0.27;0.275;0.28;0.285;0.29;0.295;0.3;0.305;0.31;0.315;0.32;0.325;0.33;0.335;0.34;0.345;0.35;0.355;0.36;0.365;0.37;0.375;0.38;0.385;0.39;0.395;0.4;0.405;0.41;0.415;0.42;0.425;0.43;0.435;0.44;0.445;0.45;0.455;0.46;0.465;0.47;0.475;0.48;0.485;0.49;0.495;0.5;0.505;0.51;0.515;0.52;0.525;0.53;0.535;0.54;0.545;0.55
6 commentaires
Stephen23
le 26 Oct 2020
>> str = '0.0;0.005;0.01;0.015;0.02;0.025;0.03;0.035;0.04;0.045;0.05;0.055;0.06;0.065;0.07;0.075;0.08;0.085;0.09;0.095;0.1;0.105;0.11;0.115;0.12;0.125;0.13;0.135;0.14;0.145;0.15;0.155;0.16;0.165;0.17;0.175;0.18;0.185;0.19;0.195;0.2;0.205;0.21;0.215;0.22;0.225;0.23;0.235;0.24;0.245;0.25;0.255;0.26;0.265;0.27;0.275;0.28;0.285;0.29;0.295;0.3;0.305;0.31;0.315;0.32;0.325;0.33;0.335;0.34;0.345;0.35;0.355;0.36;0.365;0.37;0.375;0.38;0.385;0.39;0.395;0.4;0.405;0.41;0.415;0.42;0.425;0.43;0.435;0.44;0.445;0.45;0.455;0.46;0.465;0.47;0.475;0.48;0.485;0.49;0.495;0.5;0.505;0.51;0.515;0.52;0.525;0.53;0.535;0.54;0.545;0.55';
>> vec = sscanf(str,'%f;')
vec =
0.00000
0.00500
0.01000
0.01500
0.02000
0.02500
0.03000
0.03500
0.04000
0.04500
0.05000
0.05500
... more lines here
0.51500
0.52000
0.52500
0.53000
0.53500
0.54000
0.54500
0.55000
Akira Agata
le 26 Oct 2020
Another solution:
str = '0.0;0.005;0.01;0.015;0.02;0.025;0.03;0.035;0.04;0.045;0.05;0.055;0.06;0.065;0.07;0.075;0.08;0.085;0.09;0.095;0.1;0.105;0.11;0.115;0.12;0.125;0.13;0.135;0.14;0.145;0.15;0.155;0.16;0.165;0.17;0.175;0.18;0.185;0.19;0.195;0.2;0.205;0.21;0.215;0.22;0.225;0.23;0.235;0.24;0.245;0.25;0.255;0.26;0.265;0.27;0.275;0.28;0.285;0.29;0.295;0.3;0.305;0.31;0.315;0.32;0.325;0.33;0.335;0.34;0.345;0.35;0.355;0.36;0.365;0.37;0.375;0.38;0.385;0.39;0.395;0.4;0.405;0.41;0.415;0.42;0.425;0.43;0.435;0.44;0.445;0.45;0.455;0.46;0.465;0.47;0.475;0.48;0.485;0.49;0.495;0.5;0.505;0.51;0.515;0.52;0.525;0.53;0.535;0.54;0.545;0.55';
vec = split(str,';');
vec = str2double(vec);
GS76
le 26 Oct 2020
Thank you Akira, much appreciated!
GS76
le 26 Oct 2020
Thank you Stephen, much appreciated!
Rik
le 26 Oct 2020
Adding a clarification: you don't even need to cast the string to a char, either solution can handle strings as well.
GS76
le 26 Oct 2020
Thank you Rik. This is an important point.
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