selecting only the numbers from a string variable

Dear all,
I have
A={'BARI 500G' ...
'DUR NOR 18CONmS' ...
'SENSO NORM ST-TUB 75ML '...
'MARL 100S 20CIG'...
'BI BOY WHI RMAL DU NA 15 SK'...
'REGU KR GRA ME FAMIAL 1000 ST GRND'
};
I was wondering if there is a way to choose the numbers from A. In case i have 2 numbers in a string I want to select the second one
For instance,
B=[500 18 78 20 15 1000]

5 commentaires

antonet
antonet le 10 Juil 2012
sorry for the format. I tried but could not fix it
antonet
antonet le 10 Juil 2012
I know. it is a tough question but only you can help me
Tom
Tom le 10 Juil 2012
Num = regexp(A,'\d') tells you where the digits are, but you'll have to do some work to make those into numbers- for example '1000' will come up as 4 results are there are 4 digits, even though they make one number
antonet
antonet le 10 Juil 2012
I see. So there is not any automatic way. Ok!thanks
@Antonet: Do you need those numbers as a vector??

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 Réponse acceptée

Tom
Tom le 10 Juil 2012
B = regexp(A,'\d*','Match');
returns one result for each number found in each string. You will then have to get the last value of each cell and convert it to an array (using str2double)

4 commentaires

Just that you need to convert cell that comes from 4th row before using str2double
antonet
antonet le 10 Juil 2012
can you show me how to do this. Your approach is actually what I want
thanks
B = regexp(A,'\d*','Match');
for ii= 1:length(B)
if ~isempty(B{ii})
Num(ii,1)=str2double(B{ii}(end));
else
Num(ii,1)=NaN;
end
end
Num
antonet
antonet le 10 Juil 2012
Perfect!

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Plus de réponses (2)

Luffy
Luffy le 10 Juil 2012
C = regexp(A,'[0-9]','match');
disp(C)
So do you need to just display those numbers/return them as a vector

2 commentaires

antonet
antonet le 10 Juil 2012
Modifié(e) : antonet le 10 Juil 2012
yes, as a vector. thanks
Tom
Tom le 10 Juil 2012
If you want a vector, what do you want for if there is no match for a particular line of the string?

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GS76
GS76 le 26 Oct 2020

0 votes

To whom it may concern:
I have the numbers below in a 1x1 string. How do I seperate them into seperate rows or columns? I want all the numbers between ";" (semi-colons).
Any assistance would be greatly appreciated.
0.0;0.005;0.01;0.015;0.02;0.025;0.03;0.035;0.04;0.045;0.05;0.055;0.06;0.065;0.07;0.075;0.08;0.085;0.09;0.095;0.1;0.105;0.11;0.115;0.12;0.125;0.13;0.135;0.14;0.145;0.15;0.155;0.16;0.165;0.17;0.175;0.18;0.185;0.19;0.195;0.2;0.205;0.21;0.215;0.22;0.225;0.23;0.235;0.24;0.245;0.25;0.255;0.26;0.265;0.27;0.275;0.28;0.285;0.29;0.295;0.3;0.305;0.31;0.315;0.32;0.325;0.33;0.335;0.34;0.345;0.35;0.355;0.36;0.365;0.37;0.375;0.38;0.385;0.39;0.395;0.4;0.405;0.41;0.415;0.42;0.425;0.43;0.435;0.44;0.445;0.45;0.455;0.46;0.465;0.47;0.475;0.48;0.485;0.49;0.495;0.5;0.505;0.51;0.515;0.52;0.525;0.53;0.535;0.54;0.545;0.55

6 commentaires

>> str = '0.0;0.005;0.01;0.015;0.02;0.025;0.03;0.035;0.04;0.045;0.05;0.055;0.06;0.065;0.07;0.075;0.08;0.085;0.09;0.095;0.1;0.105;0.11;0.115;0.12;0.125;0.13;0.135;0.14;0.145;0.15;0.155;0.16;0.165;0.17;0.175;0.18;0.185;0.19;0.195;0.2;0.205;0.21;0.215;0.22;0.225;0.23;0.235;0.24;0.245;0.25;0.255;0.26;0.265;0.27;0.275;0.28;0.285;0.29;0.295;0.3;0.305;0.31;0.315;0.32;0.325;0.33;0.335;0.34;0.345;0.35;0.355;0.36;0.365;0.37;0.375;0.38;0.385;0.39;0.395;0.4;0.405;0.41;0.415;0.42;0.425;0.43;0.435;0.44;0.445;0.45;0.455;0.46;0.465;0.47;0.475;0.48;0.485;0.49;0.495;0.5;0.505;0.51;0.515;0.52;0.525;0.53;0.535;0.54;0.545;0.55';
>> vec = sscanf(str,'%f;')
vec =
0.00000
0.00500
0.01000
0.01500
0.02000
0.02500
0.03000
0.03500
0.04000
0.04500
0.05000
0.05500
... more lines here
0.51500
0.52000
0.52500
0.53000
0.53500
0.54000
0.54500
0.55000
Another solution:
str = '0.0;0.005;0.01;0.015;0.02;0.025;0.03;0.035;0.04;0.045;0.05;0.055;0.06;0.065;0.07;0.075;0.08;0.085;0.09;0.095;0.1;0.105;0.11;0.115;0.12;0.125;0.13;0.135;0.14;0.145;0.15;0.155;0.16;0.165;0.17;0.175;0.18;0.185;0.19;0.195;0.2;0.205;0.21;0.215;0.22;0.225;0.23;0.235;0.24;0.245;0.25;0.255;0.26;0.265;0.27;0.275;0.28;0.285;0.29;0.295;0.3;0.305;0.31;0.315;0.32;0.325;0.33;0.335;0.34;0.345;0.35;0.355;0.36;0.365;0.37;0.375;0.38;0.385;0.39;0.395;0.4;0.405;0.41;0.415;0.42;0.425;0.43;0.435;0.44;0.445;0.45;0.455;0.46;0.465;0.47;0.475;0.48;0.485;0.49;0.495;0.5;0.505;0.51;0.515;0.52;0.525;0.53;0.535;0.54;0.545;0.55';
vec = split(str,';');
vec = str2double(vec);
GS76
GS76 le 26 Oct 2020
Thank you Akira, much appreciated!
GS76
GS76 le 26 Oct 2020
Thank you Stephen, much appreciated!
Rik
Rik le 26 Oct 2020
Adding a clarification: you don't even need to cast the string to a char, either solution can handle strings as well.
GS76
GS76 le 26 Oct 2020
Thank you Rik. This is an important point.

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le 10 Juil 2012

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le 26 Oct 2020

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