Effacer les filtres
Effacer les filtres

Can I make this for loop fast?

2 vues (au cours des 30 derniers jours)
Mohammod Minhajur Rahman
Mohammod Minhajur Rahman le 28 Nov 2018
Hi, I have a for loop that do some matrix multplicaton. Here, max i and j is 2000, U_new is a matrix of size 200 by 20, K111 cell contains 2000 full matrices of size 200 by 200.
p = 0;
for i =1:max(size(K111))
for j =1:max(size(K111))
p = p + 1;
KQQ{p} = U_new'*K111{i}*K111{j}*U_new;
end
end
  2 commentaires
Matt J
Matt J le 28 Nov 2018
Are the K111 matrices symmetric?
Mohammod Minhajur Rahman
Mohammod Minhajur Rahman le 28 Nov 2018
Hi Matt, Yes, the K111 matrices are symmetric

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Réponse acceptée

Matt J
Matt J le 28 Nov 2018
Modifié(e) : Matt J le 28 Nov 2018
Here I make occasional use of MAT2TILES (Download),
UK=cell2mat( mat2tiles( U_new'*cell2mat(K111(:).') ,[20,200]).' );
KQQ= mat2tiles( UK*UK.' ,[20,20]);
KQQ=KQQ(:);
  1 commentaire
Mohammod Minhajur Rahman
Mohammod Minhajur Rahman le 28 Nov 2018
Much Thanks! It works great

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