Unusual NaN appearing from a loop

2 vues (au cours des 30 derniers jours)
Nishant Karve
Nishant Karve le 3 Déc 2018
Commenté : OCDER le 3 Déc 2018
Hi there.
I've been trying to run a loop to calculate the quartiles for each of the four columns in a dataset. The loop is as given below:
sized = size(data);
for i = 1:4
Minimum(i,1) = min(data(:,i));
Quart2(i,1) = median(data(:,i));
if rem(sized(1),2) == 0
Quart1(i,1) = median(data(data(:,1) < Quart2(i,1)));
Quart3(i,1) = median(data(Quart2(i,1) < data(:,i)));
else
Quart1(i,1) = median(Minimum(i,1): Quart2(i,1));
Quart3(i,1) = median((Quart2(i,1)):(max(data(:,i))));
end
Maximum(i,1) = max(data(:,i));
end
I'm generating a table of these results after the loop and I get something like this once I run the script:
DataSnip.PNG
The problem with this is that I don't know why the 'NaN' values appear here. When I run the line of code evaluating 'Quart1' independently in the command window for this very dataset, it gives me the correct value of 0. I'd be really grateful if someone could help me with this.
Thanks!

Réponses (1)

OCDER
OCDER le 3 Déc 2018
It seems that you are taking the median of an empty number
%EXAMPLE
data = [1 2 3];
Quart2 = 4;
Quart1 = median(data(Quart2 < data));
Quart1 =
NaN
Double check that there is no empty values. Otherwise, replace NaN's with 0's.
  2 commentaires
Nishant Karve
Nishant Karve le 3 Déc 2018
Thanks for the response and the alternative.
It doesn't seem like I have missing values in the dataset. Just ran a check.
OCDER
OCDER le 3 Déc 2018
When you do the logical index:
Quart2(i,1) < data(:,i)
It's possible that NO DATA agrees with this condition. So when you do this:
data(Quart2(i,1) < data(:,i)),
you get NO DATA, or an empty array, []. That's equivalent to doing this:
Quart1 = median([]) = NaN.
To fix, do this:
Quart1(isnan(Quart1)) = 0;

Connectez-vous pour commenter.

Catégories

En savoir plus sur Automotive dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by