Interp1 on a cell array

I have a cell array that contains some numbers and empty spaces, say

A=[ , ,4,5,6,7,,,8,,5, , ,]

I want to interpolate A using interp1('previous') so that it becomes

A=[ , ,4,5,6,7,7,7,8,8,5, , ,]

That it is a cell array is making it difficult to use interp1. What I have got so far is this:

A={betdaqv{5,:}};
x = 1:length(A);
xi = 1:length(A);
emptyloc=find(cellfun(@isempty,A));
zs = emptyloc;
A(zs)=[];
x(zs)=[];

But then applying the following doesn't work:

output1 = interp1(x, A, xi,'previous')

See attached for betdaqv.

[Stephen23]

This is not a cell array and it is not valid MATLAB syntax:

A=[ , ,4,5,6,7,,,8,,5, , ,]

Please at least give us something that we can work with.

[Image Analyst]

You forgot to attach betdaqv. Make it easy for us to help you, not hard.

Save betdaqv in a .mat file and then upload

save('answers.mat', 'betdaqv');

Once we have it, we can try things and help you.

[Sam Smith]

Thank you. I mean A should have curly brackets, not square.

Answer 1

[Stephen23]

>> A = {[],[],4,5,6,7,[],[],8,[],5,[],[]};
>> idx = find(~cellfun('isempty',A));
>> idy = idx(1):idx(end);
>> new = interp1(idx,[A{idx}],idy,'previous');
>> A(idy) = num2cell(new);
>> A{:}
ans = []
ans = []
ans =  4
ans =  5
ans =  6
ans =  7
ans =  7
ans =  7
ans =  8
ans =  8
ans =  5
ans = []
ans = []

[Sam Smith]

Thank you. I'm happy you focussed on the substance of my question.

Answer 2

[madhan ravi]

you may look into fillmissing released in 2016b

Answer 3

[Image Analyst]

In the following code, your A does not have any empty values:

s = load('answers.mat')
betdaqv = s.betdaqv
A={betdaqv{5,:}};
x = 1:length(A);
xi = 1:length(A);
emptyloc=find(cellfun(@isempty,A));
zs = emptyloc;
A(zs)=[];
x(zs)=[];

Why do you think it should?