HOW I COULD DRAW THIS FUNCTION

[madhan ravi]

upload the code that you tried

[HADIMARGO]

x=0:1:50;

syms n;
y=((2/pi)*((-1)^n+1)*(sin(pi*x)))/n;

symsum(y,n,1,inf);
figure(1);
plot(x,y)

i should say that i am a beginner.

Answer 1

[HADIMARGO]

final answer by myself!!

x=linspace(-5,5,1000);

s=0;

for n=1:1:10000

p=((-1)^(n+1)*sin(n*pi*x))/n;

s=s+p;

end

f=(2/pi)*s;

plot(x,f)

Answer 2

[madhan ravi]

Use cumsum() to define the behaviour of the alternating series:

x=linspace(0,50,10000);
n=1:10000;
y=(2/pi).*cumsum((((-1).^n+1).*(sin(pi.*x)))./n);
figure(1);
plot(x,y)

[HADIMARGO]

so tnx madhan ravi. i will send this answer to my teacher. if it correct i will get 1 score of 20 .

[madhan ravi]

Anytime :) , read more about cumsum() and linspace()

Answer 3

[HADIMARGO]

my teacher say it isnot correct. you should put it in a loop.

[Walter Roberson]

If you have TheResult = cumsum(SomeVector) then you can recode that in a loop as

TheResult(1) = SomeVector(1);
for LoopVariable = 2 : length(SomeVector)
    TheResult(LoopVariable) = TheResult(LoopVariable-1) + SomeVector(LoopVariable);
end

... Approximately.

Answer 4

[HADIMARGO]

can anyone write complete answer with loop?

[Walter Roberson]

Yes, we could, but it is your homework.