How do I ascribe a variable to a cell?

11 vues (au cours des 30 derniers jours)
Christian Huber
Christian Huber le 14 Déc 2018
Modifié(e) : madhan ravi le 14 Déc 2018
Hi,
First of all thanks for reading this and trying to help :)
I am struggling with "attaching" my script to functions written by (many) others.
For that I need to take data out of a text file. In the function (not mine) the data later gets accessed using the command: soilstructure(1).thickness
I have tried with a table and a cell array and attributed the name 'thickness' to the last column, but it wont accept it as index, at least not using the above command... The error message reads: Struct contents reference from a non-struct array object.
Here is what I have so far:
layer = readtable('soil.txt',...
'Delimiter',' ','ReadVariableNames',false);
soilstructure = table2cell(layer,...
'VariableNames',{'type' 'radius' 'G' 'nu' 'rho' 'damping' 'thickness'});
x = soilstructure(1).thickness %why can't it access the data???
The table looks as follows:
soilstructure =
4×7 cell array
'L' [0] [6.8322e+06] [0.4900] [1840] [0.0500] [ 15]
'L' [0] [6.9898e+06] [0.4900] [1840] [0.0500] [ 15]
'L' [0] [2.5479e+07] [0.4900] [1840] [0.0500] [ 85]
'H' [0] [3.3425e+07] [0.4900] [1840] [0.0500] [NaN]
Thank you so much for your help
Chris
  2 commentaires
Image Analyst
Image Analyst le 14 Déc 2018
You forgot to attach 'soil.txt'. Please attach it for the best help.
Christian Huber
Christian Huber le 14 Déc 2018
Thank you for your time. I attached it. It is just an example file though the real files are much longer...

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madhan ravi
madhan ravi le 14 Déc 2018
Modifié(e) : madhan ravi le 14 Déc 2018
The proper way to access it would be( see Accessing cell array for better understanding):
x = soilstructure{:,7} % but I don’t see your point of converting it to a cell from table but anyhow..
But if you want it to be treated as the way it was this is how I would do it:
remove soilstructure and replace it with (the reason for your error was it was a cell and you were treating it as a struct) the below , treats the data as a table as it was imported as a table
layer.Properties.VariableNames={'type'.... rest the same
layer.thickness % this will access the thickness column
  8 commentaires
Christian Huber
Christian Huber le 14 Déc 2018
It is very troubeling though since the program in it's entirety (we lost the input script and a few functions) apparently worked before. I guess I will have to change the parts that treat the struct as a cell and solve the issue that way. Can't seem to understand how it worked before though...
Again many thanks for you help Madhan!
Have a great day
Chris
madhan ravi
madhan ravi le 14 Déc 2018
Modifié(e) : madhan ravi le 14 Déc 2018
You're welcome Chris , I suggest you to contact the person who coded the script so that you know what he/she mean by this.

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Plus de réponses (1)

Mark Sherstan
Mark Sherstan le 14 Déc 2018
Modifié(e) : Mark Sherstan le 14 Déc 2018
It is a cell array not a structure. Retrieve the information as follows:
x = soilstructure{1,7}

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