Finding a vector as a subset of an array

I have

a = [2 2];
b = [2 3];

How to find that 'b' contains all the elements of 'a' i.e. here two 2's. Here 'b' contains only one '2'.

[Bruno Luong]

so in the above example the result should be FALSE right?

Answer 1

[Bruno Luong]

[u,~,j] = unique(a(:));
[tf,loc] = ismember(b(:),u);
s = [length(u),1];
result = all(accumarray(j(:),1,s) <= accumarray(loc(tf),1,s))

[Prasanna Venkatesh]

Thanks! But still one more query. Suppose,

a = [2 3 2 5 2];
b = [2 7 2];

I need to find the missing elements of 'a' in 'b'. Here the elements are one '2', one '3' and one '5'.

[Bruno Luong]

a = [2 3 2 5 2 7];
b = [2 7 2 6];

% Same as above, juste decomposing for re-user later
[u,~,j] = unique(a(:));
[tf,loc] = ismember(b(:),u);
s = [length(u),1];
n = accumarray(j(:),1,s)-accumarray(loc(tf),1,s);
anotin = n>0;
bcontaina = all(~anotin)

n = n(anotin);
anotin = u(anotin);
anotin = table(anotin, n)

Returns

bcontaina =

  logical

   0


anotin =

  3×2 table

    anotin    n
    ______    _

      2       1
      3       1
      5       1

[Prasanna Venkatesh]

Thanks Bruno Luong !

Answer 2

[madhan ravi]

a = [2 2];
b = [2 3];
idx=ismember(b,a);
all(idx)       % if zero then b doesn't contain all the elements of a else vice versa

[Prasanna Venkatesh]

Thanks! But still one more query. Suppose,

a = [2 3 2 5 2];
b = [2 7 2];

I need to find the missing elements of 'a' in 'b'. Here the elements are one '2', one '3' and one '5'.