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Help regarding parallelizing code

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Soumyadipta Sengupta
Soumyadipta Sengupta le 17 Déc 2018
Rouvert : Walter Roberson le 22 Déc 2018
for i=1:(length(water)/3)-1
for j=i+1:length(water)/3
donor_mol_index=[i j]; %between 2 water molecules either can be donor/acceptor
for p=donor_mol_index
donor_h_index=[1 3];% water atom data 1st and last atoms are hydrogen atoms
for k=donor_h_index
hb_ww_count=hb_ww_count+1;
%di-donor index, ai-acceptor index, donor is the molecule which gives the h-atom
if p==i
di=i; ai=j; %if donor molecule index equals i
else
di=j;ai=i;%if donor molecule index equals j
end
%dist_ww(cnt_steps,hb_ww_count)=sqrt(sum((water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5)).^2));
v1=water_mol(di).atom_data(k,3:5)-water_mol(di).atom_data(2,3:5);%vector connecting donor hydrogen-donor oxygen
v2=water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5);%vector connecting donor hydrogen-acceptor oxygen
angle=acos(dot(v1, v2) / (norm(v1) * norm(v2)));
angle_ww(cnt_steps,hb_ww_count)=radtodeg(angle);
if sum((water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5)).^2)<=dist_hb^2 %distance between donor hydrogen and acceptor oxygen
v1=water_mol(di).atom_data(k,3:5)-water_mol(di).atom_data(2,3:5);%vector connecting donor hydrogen-donor oxygen
v2=water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5);%vector connecting donor hydrogen-acceptor oxygen
angle=acos(dot(v1, v2) / (norm(v1) * norm(v2)));
angle=radtodeg(angle);
if angle<=angle_hb
hb_ww(cnt_steps,hb_ww_count)=1;
end
else
hb_ww(cnt_steps,hb_ww_count)=0;
end
end
end
end
end
I would like to parallelize the outer loop. Can I put all the code inside the first for loop in a function and supply the loop variable i and the structures to the function ? hb_ww_count is a reduction variable. I use this variable for indexing another array within my code.
Please provide some suggestions. I am sort of lost.
  2 commentaires
Jan
Jan le 17 Déc 2018
Start with simplifying your code: why do you calculate v1 and v2 and the angle twice? Change:
v1=water_mol(di).atom_data(k,3:5)-water_mol(di).atom_data(2,3:5);%vector connecting donor hydrogen-donor oxygen
v2=water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5);%vector connecting donor hydrogen-acceptor oxygen
angle=acos(dot(v1, v2) / (norm(v1) * norm(v2)));
angle_ww(cnt_steps,hb_ww_count)=radtodeg(angle);
if sum((water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5)).^2)<=dist_hb^2 %distance between donor hydrogen and acceptor oxygen
v1=water_mol(di).atom_data(k,3:5)-water_mol(di).atom_data(2,3:5);%vector connecting donor hydrogen-donor oxygen
v2=water_mol(di).atom_data(k,3:5)-water_mol(ai).atom_data(2,3:5);%vector connecting donor hydrogen-acceptor oxygen
angle=acos(dot(v1, v2) / (norm(v1) * norm(v2)));
to:
% Before the loops:
dist_hb2 = dist_hb ^ 2; % Once only
len = floor(length(water)/3);
n = 4 * (len - 1) * len / 2;
hb_ww = zeros(cnt_steps, n); % Pre-allocate!!!
angle_ww = zeros(cnt_steps, n);
...
v1 = water_mol(di).atom_data(k,3:5) - water_mol(di).atom_data(2,3:5);%vector connecting donor hydrogen-donor oxygen
v2 = water_mol(di).atom_data(k,3:5) - water_mol(ai).atom_data(2,3:5);%vector connecting donor hydrogen-acceptor oxygen
angle = acos(dot(v1, v2) / (norm(v1) * norm(v2))); % Not accurate, prefer atan2
angle_ww(cnt_steps, hb_ww_count) = angle * (180 / pi);
if sum(v2 .^ 2) <= dist_hb2 %distance between donor hydrogen and acceptor oxygen
if angle<=angle_hb
hb_ww(cnt_steps, hb_ww_count)=1;
end
end
end
With avoiding repeated calculation and a proper pre-allocation the code is at least efficient without parallelizing.
Soumyadipta Sengupta
Soumyadipta Sengupta le 17 Déc 2018
preallocation of all the arrays and structures have been done but not shown here.

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Réponses (2)

Soumyadipta Sengupta
Soumyadipta Sengupta le 17 Déc 2018
Hello Jan,
I have preallocated those variables as well as the structures . I didn't show the complete code.
  2 commentaires
Jan
Jan le 17 Déc 2018
Please post comments inthe section for comments. Not showing the relevant part of the code, especially the pre-allocation, is not helpful for the readers.
Soumyadipta Sengupta
Soumyadipta Sengupta le 17 Déc 2018
Even without the double angle calculation, each inner loop takes around 0.5 secs on a 2.6 ghz core. i would have to run approx 2000 such inner loops and 2000 such outer loops

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Soumyadipta Sengupta
Soumyadipta Sengupta le 22 Déc 2018
i have parallelized it.

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