customized 2D Cartesian plot

4 vues (au cours des 30 derniers jours)
BeeTiaw
BeeTiaw le 20 Déc 2018
Commenté : BeeTiaw le 20 Déc 2018
Dear expert,
Could anyone help me to customize a Cartesian plot? the problem is as follow:
I have the following dataset which I want to plot into Cartesian axis.
data=[
% x y Temp
0.8470 0.0805 -0.6176
0.8476 0.1598 -0.6179
0.8477 0.2376 -0.6157
0.8471 0.3141 -0.6131
0.8466 0.3894 -0.6156
0.8469 0.4622 -0.6228
0.8477 0.5311 -0.6255
0.8480 0.5953 -0.6130
0.8472 0.6551 -0.5939
0.8461 0.7109 -0.6022
0.8465 0.7612 -0.6653
0.8485 0.8024 -0.7563
0.8492 0.8309 -0.2977
0.8431 0.8456 5.6075
0.8251 0.8494 8.3770
0.7932 0.8479 4.9443
0.7493 0.8462 3.7959
0.6973 0.8463 3.3363
0.6405 0.8475 3.1260
0.5796 0.8480 2.9271
0.5143 0.8475 2.6897
0.4443 0.8467 2.5026
0.3707 0.8467 2.4095
0.2951 0.8473 2.3851
0.2182 0.8478 2.3667
0.1401 0.8475 2.3135
0.0604 0.8469 2.2550];
The first and second colums are the coordinate of a quater-square in {x,y} and the third column is the measurement.
The value in the third column is to be plotted as shown in the figure below.
The "zero" of each "Temp" starts at the boundary of their corresponding {x,y}
How can I achieve this?
Thank you in advance...
  2 commentaires
KALYAN ACHARJYA
KALYAN ACHARJYA le 20 Déc 2018
As per what I have undestood from your question- you want to plot (x,y) position in xy plane with temp value, right?
It would be go for 3D bar plot.
Or
two yy axis, could you please clarify more (graph shown in your question)?
BeeTiaw
BeeTiaw le 20 Déc 2018
Hi Kalyan,
That's correct: to plot (x,y) position in xy plane with temp value.

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Réponses (1)

KSSV
KSSV le 20 Déc 2018
x = data(:,1) ; y = data(:,2) ; z = data(:,3) ;
figure
plot3(x,y,z);
figure
scatter(x,y,20,z,'filled')
  1 commentaire
BeeTiaw
BeeTiaw le 20 Déc 2018
Thanks, but this code does not produce a 2D plot as shown in the example.

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